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4 years ago

What is the answer for both

Mathematics

2 answers:

ivann1987 [24]4 years ago

4 0

Francisco because he ate 4/6 which is 66% closest to beat it is the people who ate 3/6 and 1/2 because they ate 50%

tatiyna4 years ago

3 0

A is for Alexis and F is for Francisco

A = 1/6 + 1/2 + 1/2 = 1 and 1/6
F = 2/3 + 1/2 + 1/3 = 1 and 1/2

1 1/6 < 1 1/2
A < F
Francisco ate the most pie.

1/6 of cherry pie is left.
No apple pie is left.
1/6 blueberry pie is left.

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One of my cats, Apollo, drives a cat car. He used 6/8 of a tank of gas to visit his friends for the weekend, and another 1 half

Arlecino [84]

Answer:

Total gas used = 3/2 of a tank of gas

Step-by-step explanation:

Visit to friend = 6/8 of a tank of gas

Commute to work = 1/2 of a tank of gas

Weekend trip = 1/4 of a tank of gas

Total gas used = Visit to friend + Commute to work + Weekend trip

= 6/8 + 1/2 + 1/4

= 6+4+2/8

= 12/8

= 3/2

Total gas used = 3/2 of a tank of gas

7 0

3 years ago

Write a decimal equation that has a product of 3.15

Vaselesa [24]

<span>you could have 3.15=100 times 0.0315, 10 times 0.315.</span>

4 0

3 years ago

Find the value of x

riadik2000 [5.3K]

Answer:

4√5

Step-by-step explanation:

Use Pythagorean theorem

a^2=21^2-19^2

a^2=441-19^2

a^2=441-361

a^2=80

a= √80

simplify

6 0

3 years ago

What The probability is

lianna [129]

A) P( Jordan finishes before Jacobs)= 2/5 = 0.40
P( Jacobs finishes before Julia) = 3/5 = 0.60
P(Jordan finishes before Jacobs AND before Julia) = 0.40 x 0.60 = 0.24

b)P( Jordan finishes before Jacobs)= 2/5 = 0.40 (already calculated

3 0

3 years ago

2. A motorcycle rider moving with initial velocity of 15.0 m/s uniformly accelerates to a speed of 30.0 m/s in a.

xenn [34]

Given :

Initial velocity , u = 15 m/s .

Final velocity , v = 30 m/s .

Distance travelled , d = 40 m .

Also , this body is uniformly accelerating .

To Find :

(a) What is the acceleration .

(b) How long does this take .

Solution :

Let , acceleration be a .

By , equation of motion :

$v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{30^2-15^2}{2\times 40}\\\\a=8.44\ m/s^2$

Also , by equation :

$v=u+at\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{30-15}{8.44}\ s\\\\t=1.78\ s$

Hence , this is the required solution .

3 0

3 years ago