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3 years ago

I bought 3 Books my total is 150$ 1 book is 50% more expensive than all of them how much is it

Mathematics

1 answer:

Olin [163]3 years ago

5 0

Answer:

The more expensive book cost $90, the other two combined cost $60.

Step-by-step explanation:

x = cost of more expensive book

y = subtotal cost of the other books

x = 50% more than y, so x = 1.50y = 1.5y

x + y = total cost = $150

1.5y + y = 150

y = 150/2.5 = 60

x = 1.5y = 1.5(60) = 90

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A sixth grade class is going on a field trip. The school is providing a one sack lunch for each student. Each lunch has either a

vova2212 [387]

Answer:

List 2

Step-by-step explanation:

List 1 mentions that there is "Ham, Carrots, celery". We know that students can only have <em>either </em>carrots or celery, but the list shows that the students have both. Therefore, list 2 is correct.

3 0

3 years ago

a circle is divided into 18 equal parts how many degrees is the angle for each part? how many degrees is the angle for 5 parts?

Ket [755]

There are 360 degrees in a circle, and we have 18 pieces, so we need to see how many times 18 goes into 360. We can find this out by dividing.

360/18=20

You can check this by multiplying 20 and 18 (it equals 360)!

So, each fraction of the circle will be 20 degrees.

If you take 5 of these 20 degree pieces, you'll need to multiply them by 20 to see how many degrees they'd be.

You need to multiply by 20 because each piece is 20 degrees, and we need to find how many degrees 5 pieces is. It's the same as doing
20+20+20+20+20! :)

20*5=100. 5 parts will be 100 degrees.

Hope I helped! :)

4 0

3 years ago

A manager bought 12 pounds of peanuts for $30. He wants to mix $5 per pound cashews with the peanuts to get a batch of mixed nut

seraphim [82]

Answer:

18 pounds of cashews are needed.

Step-by-step explanation:

Given;

A manager bought 12 pounds of peanuts for $30.

Price of peanut per pound P = $30/12 = $2.5

Price of cashew per pound C = $5

Price of mixed nut per pound M = $4

Let x represent the proportion of peanut in the mixed nut.

The proportion of cashew will then be y = (1-x), so;

xP + (1-x)C = M

Substituting the values;

x(2.5) + (1-x)5 = 4

2.5x + 5 -5x = 4

2.5x - 5x = 4 -5

-2.5x = -1

x = 1/2.5 = 0.4

Proportion of cashew is;

y = 1-x = 1-0.4 = 0.6

For 12 pounds of peanut the corresponding pounds of cashew needed is;

A = 12/x × y

A = 12/0.4 × 0.6 = 18 pounds

18 pounds of cashews are needed.

4 0

3 years ago

Verify the Identity

valina [46]

Answer:

Cos x sec^2 x

Cos x (1 + cot x)

Cos x / sin x • 1

Step-by-step explanation:

5 0

3 years ago

44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access

DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.

FileSystemLocked → ∀x Access(x, SystemMailbox)

(c)

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0

3 years ago