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Natasha_Volkova [10]
3 years ago
7

I bought 3 Books my total is 150$ 1 book is 50% more expensive than all of them how much is it

Mathematics
1 answer:
Olin [163]3 years ago
5 0

Answer:

The more expensive book cost $90, the other two combined cost $60.

Step-by-step explanation:

x = cost of more expensive book

y = subtotal cost of the other books

x = 50% more than y, so x = 1.50y = 1.5y

x + y = total cost = $150

1.5y + y = 150

y = 150/2.5 = 60

x = 1.5y = 1.5(60) = 90

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Brainliest to first correct answer.
tester [92]

The answer is x = -0.6 and y = -8.2.

8 0
3 years ago
Janice is 7 years older than Tam. Complete the table, and then graph this situation.
qwelly [4]

Answer:

The table in the exercise can be completed with the next results:

  • x          y
  • 2         <u>9</u>
  • 4         <u>11</u>
  • 6         <u>13</u>
  • 8         <u>15</u>

Step-by-step explanation:

As in the exercise Janice is 7 years older than Tam, to obtain the result in the table, you must add 7 to each age in the column x, with this we can make the next formula:

  • y = x + 7

Remember that x is Tam's age, and y is Janice's age, so, you must replace the x variable in each case to obtain the result to y:

When x is 2:

  • y = 2 + 7
  • <u>y = 9</u>

When x is 4:

  • y = 4 + 7
  • <u>y = 11</u>

When x is 6:

  • y = 6 + 7
  • <u>y = 13</u>

When x is 8:

  • y = 8 + 7
  • <u>y = 15</u>

At last, <u>to obtain the graph you can use the formula made: y = x + 7</u>, and you'll obtain a graph like the attached picture, <em>where each time x obtain a unit, the y variable obtain a unit too maintaining the diference of 7</em>.

8 0
2 years ago
How do do the work for 12c+6c=36
BlackZzzverrR [31]
Apologies for the bad handwriting.

5 0
3 years ago
Read 2 more answers
Please help with this I am completely stuck on it
vaieri [72.5K]

Answer:

f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4

Step-by-step explanation:

Given:

The function, H(x)=\sqrt[3]{6x^{2}-4}

Solution 1:

Let f(x)=\sqrt[3]{x}

If f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}, then,

\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4

Solution 2:

Let f(x)=\sqrt[3]{x-4}. Then,

f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}

Similarly, there can be many solutions.

7 0
3 years ago
If you sleep 33% in a day, how many hours is that?
strojnjashka [21]
We know that
one day is equal to 24 hrs
so
33 % of the day is equal to
(\frac{33}{100} )*24 \\ =7.92 hrs

the answer is
7.92 hrs
5 0
2 years ago
Read 2 more answers
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