Question

A new Youth Activity Center is being built in Hadleyville. The perimeter of the rectangular playing field is 442 yards. The length of the field is 4 yards less than quadruple the width. What are the dimensions of the playing​ field?

Answer 1

Answer:

45 yards and 176 yards

Step-by-step explanation:

Perimeter of a rectangular playing field = 2(Length + width)

P = 2(L+W)..................... Equation 1

From the question,

Let the width of the rectangular playing field = x yards,

The the Length = 4x-4 yards.

Given: P = 442 yards.

Substitute these values into equation 1

442 = 2(4x-4+x)

442/2 = 5x-4

221 = 5x-4

5x = 221+4

5x = 225

x = 225/5

x = 45 yards.

Width = 45 yards.

Length = (45×4)-4 yards = 176 yards

Hence the dimensions of the playing field are, 45 yards and 176 yards