f(x) = -720h + 10080
10080 is the total amount of water in the pool, 720 is the amount of water you lose each hour.
"h" is the number of hours the pool has been draining, and since you know the pool has been draining for 12 hours, you can plug in 12 for "h".
f(x) = -720h + 10080
f(x) = -720(12) + 10080
f(x) = -8640 + 10080
f(x) = 1440
After 12 hours of draining, 1440 is the amount of water left in the pool. (I don't know the units [ex: gallons, etc.])
The equation below does not have one solution, or no solutions, but instead it has an infinite number of solutions
<h3>How to determine whether the equation below has a one solutions, no solutions, or an infinite number of solutions?</h3>
The equation is given as:
x + 2 = 2 + x
Collect the like terms
x - x =2 - 2
Evaluate the like terms
0 = 0
An equation that has a solution of 0 = 0 has an infinite number of solutions
Possible values of x are x = 8 and x = -8
Hence, the equation below does not have one solution, or no solutions, but instead it has an infinite number of solutions
Read more about number of solutions at
brainly.com/question/24644930
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When turning a fraction into a decimal, any whole numbers comes before the "." and the fraction will become after the ".".
To make it simple, turn the fraction into a "over 100" fraction to make it easier.
Multiple both numeriator and denominator by a specific number, to turn the denominator into a 100. You must times the numeriator as well since your changing the denominator.
100 / 5 = 20
So now, multiple both sides of the fraction by 20.
3 x 20 = 60
5 x 20 = 100
2 60/100
Now, put the whole number in front of the decimal symbol.
2.___
Now, take the numeriator and put it behind the decimal symbol.
2.60
So, when turning 2 3/5 into a decimal, it is 2.60.
Multiply by 60, there are 60 seconds in a minute. It would be 1206 meters/minute
Answer:
A) f'(3) < f'(0) < f'(-2)
Step-by-step explanation:
You don't need to create a graph of the derivative. Remember that the derivative is the slope/rate of change of a function at a certain point!
At f(-2), you can see that the function is increasing around it, which suggests that f'(-2) is positive.
At f(0), you can see that the function doesn't increase nor decrease around it, which suggests that f'(0) is 0 (or no slope!).
At f(3), you can see that the function is decreasing around it, which suggests that f'(3) is negative.
This must mean that f'(3) < f'(0) < f'(-2)
I hope this clears things up, and please ask questions in the comments if you are still confused! I want to help you!
