Introduced to a habitat similar to their own introduced to a habitat different than their own outcompete native species generally have no native predators generally have native predators often have high reproductive rates often have low reproductive rates can tolerate a range of conditions
Needed:
Co2
Water
Solar Energy(Sunlight)
Produced:
02
Glucose for the plant to use for survival
Answer:
c) Emus ostriches and meas are similar to the glyptodon
Explanation:
Only answer that supports the idea of evolution.
Answer:
17
Explanation:
In corn,
Smooth kernel (S) is dominant to rough kernel (s)
Purple kernel (P) is dominant to yellow kernel (p)
Since no information has been given about the cross here let us assume it to be a standard dihybrid cross.
The phenotypic ratio of dihybrid cross is 9:3:3:1. 9/16 will show dominant phenotype for both traits, 3/16 will show dominant phenotype for one trait, other 3/16 will show dominant phenotype for the second trait, 1/16 will have recessive phenotype for both the traits.
Here,
Purple rough (P_ss) = 52
Yellow smooth (ppS_) = 50
Both of them show dominant phenotype for one trait so they each form 3/16 of the progeny.
If the total progeny was z, 3/16*z = 50
z = (50*16)/3 = 267
Total progeny = 267 kernels
Yellow rough kernels (ppss) = (1/16*267) = 17
So approximately 17 corn kernels will be yellow and rough.
