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docker41 [41]
3 years ago
15

Looking at the chart above, the students need to develop a classification scheme to distinguish plant and animal cells. The pres

ence of which of the following structures/organelles would be most useful for this purpose?
Biology
2 answers:
sladkih [1.3K]3 years ago
8 0
Can't see the chart. But chloroplasts, cell wall, central vacuole are only in plant cells
AlladinOne [14]3 years ago
7 0

Answer: the answer for studyisland is cell wall

Explanation:

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An adaptive radiation is________.
erastovalidia [21]

The correct answer is A. A burst of speciation

Explanation:

Adaptative radiation is part of evolution and occurs when a single organism or species diversify into a wide range of species (speciation), this process is called "adaptative" because the speciation occurs due to changes in the environment that make challenging survival usually due to the reduction of resources available and therefore organisms change to adapt to new conditions. Additionally, in adaptive radiation, the new organisms share traits with their common ancestor but also have different and unique traits. Considering this, it can be concluded adaptative radiation a burst of speciation.

8 0
3 years ago
Does either the mother or the father in a have dimples
dsp73
Idk? I can’t see a picture to let me know if they do or not
4 0
3 years ago
Suppose a species of bird called the red-crested warbler has a plumage length that is controlled by a single gene. The Plm allel
AleksAgata [21]

We are going to have different allele frequencies for the two populations

North American:

72 birds total => 144 alleles

72 - 55 birds = 17 short plume birds.

q^2 = (2*17) / 114 = 0.236

Freq(short plume allele) = q = 0.486

Freq(long plume allele) = p = 1 - q = 0.514

From this North American population we get

0.486 * 114 = 55 long plume alleles

0.514 * 114 = 59 short plume alleles

South American:

252 birds total => 504 alleles

252 - 75 birds = 177 short plume birds.

q^2 = (2*177) / 504 = 0.702

Freq(short plume allele) = q = 0.838

Freq(long plume allele) = p = 1 - q = 0.162

From this South American population we get

0.162 * 504 = 82 long plume alleles

0.838 * 504 = 422 short plume alleles

Blended population has

55 + 82 = 137 long plume alleles

59 + 422 = 481 short plume alleles

137 + 481 = 618 total alleles

p = 137/618 = 0.222

q = 481/618 = 0.778

The new population has the p and q from the blended population. The new population has 1000 individuals. The portion of long plumed will be homozygote long plumage + heterozygote, which is p^2 + 2pq, and you multiply that by the population size 1000 to get the final answer.

population size * (p^2 + 2pq) = 1000 * (0.222^2 + 2*0.222*0.778) = 395 birds (answer)

6 0
3 years ago
What was the full name of the study and what was it intended to examine? "Miss Evers' Boys"
Mariana [72]
Miss every boys i think i dont really know
6 0
3 years ago
The basic building block of life is _____.
lutik1710 [3]
I am assuming that since you are in a biology class, you are looking for the answer: cells.

Hope this helps! <3
4 0
3 years ago
Read 2 more answers
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