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3 years ago

What 50 times 201 plz answer For zoom Meeting Id:615 012 5518 Password: 4ZL13U

Mathematics

1 answer:

bogdanovich [222]3 years ago

8 0

10,050, 50 times 200 equals 10,000, 50 times 1 equals 50, so 10,000+50=10,050

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When writing fraction from a graph does the x axis number go on top or bottom

Harlamova29_29 [7]

Answer:

x ax-s can be horizontal and top

y axis is bottom

Step-by-step explanation:

8 0

4 years ago

Viết các lũy thừa sau dưới dạng một lũy thừa hoặc các tích các lũy thừa có số nguyên và số nguyên A.8 mũ 2 B. 654

Semmy [17]

Step-by-step explanation:

câu trả lời là trong hình ảnh trên

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3 years ago

1.1

solniwko [45]

Answer:

$Cost = 112.266$ cent/km

Step-by-step explanation:

Given

$Unit\ cost = R17.82/litre$

$Rate = 6.3litre/100km$

Required

The fuel cost in $cent\ per\ km$

This is calculated using:

$Cost = Unit\ cost * Rate$

$Cost = R17.82/litre * 6.3litre/100km$

$Cost = R17.82 * 6.3/100km$

$Cost = R1.12266/km$

Multiply by $100$ to get the cost in cents

$Cost = 1.12266 * 100$ cent/km

$Cost = 112.266$ cent/km

6 0

3 years ago

I need help solving the last 2 questions please

Alborosie

A. 7.5 pages per hour B. $2.66 for one page

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3 years ago

Read 2 more answers

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

i.e. $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

Formula : $P(x=r)=^nC_r p^r q ^ {n-r}$

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=0.390748$

Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907

5 0

3 years ago