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Step2247 [10]
3 years ago
8

Can someone help with this question i need it done asap!! will give you all my points and brainliest.

Mathematics
1 answer:
liq [111]3 years ago
7 0

Answer:


Step-by-step explanation:

Here, the two triangles are congruent.

we know, for congruent triangles-

corresponding sides are congruent.

From the figures, we get

triangle PQR is congruent to triangle LKJ

Here,

corresponding sides are-

PQ and LK ; QR and KJ ; PR and LJ

Hence, we get

PQ ≅ LK ; QR ≅ KJ ; PR ≅ LJ

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In a triangle ABC, AB = 7, AC = 8, BC = 3, what is cos(A)?
kotegsom [21]
Use the cosine rule.
c=AB=7
b=AC=8
a=BC=3
a^2=b^2+c^2-2bc(cos(A)) 
=>
cos(A)=(b^2+c^2-a^2)/(2bc)
=(7^2+8^2-3^2)/(2*7*8)
=13/14
=0.9286
6 0
3 years ago
backyard garden rectangular in shape. determine the best length and width(in feet). how many feet of fencing would be needed? us
olga2289 [7]
L = building side
W = non-building side

P = 2W + L = 42 (note only one L because the other L is the building itself)

Solve for L:

L = 42 - 2W


Area = l*w
Area = (42-2W)W = 42W - 2W2

Let area be y, so y = -2W2 +42W

Note this is a parabola pointing down because the coefficient of the W2 is negative. That makes the vertex the maximum for which we are searching.

Vertex of this parabola is at W=-b/2a, if the quadratic is aW2 + bW + c = 0

a = -2
b = 42

W = -42/(2*-2) = -42/-4 = 10.5

W = 10.5
L = 42-2(10.5) = 42-21 = 21

Area = L*W = 21 * 10.5

A = 220.5 ft2
8 0
3 years ago
The equation for the circle is (x-2)^2 + (y-1)^2 = 4<br><br> True<br> or<br> False???
jasenka [17]
True because the center is (2,1) and radius is 2
8 0
3 years ago
Read 2 more answers
Use the divergence theorem to calculate the surface integral z s ~f d~s ; that is, calculate the ux of ~f across s, where ~f = z
MAXImum [283]
By the divergence theorem,

\displaystyle\iint_S\mathbf f\cdot\mathrm d\mathbf S=\iiint_R(\nabla\cdot\mathbf f)\,\mathrm dV

where R is the solid whose boundary is S. We have

\nabla\cdot\mathbf f=\dfrac{\partial z}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial zx}{\partial z}=1+x

so we set up the volume integral as

\displaystyle\iiint_R(\nabla\cdot\mathbf f)\,\mathrm dV=\int_{x=0}^{x=1/a}\int_{y=0}^{y=(1-ax)/b}\int_{z=0}^{z=(1-ax-by)/c}(1+x)\,\mathrm dz\,\mathrm dy\,\mathrm dx
=\dfrac{4a+1}{24a^2bc}
7 0
4 years ago
What transformation has changed the parent function f(x) = log3x to its new appearance shown in the graph below?
irina [24]

Answer: Third option

f(x) - 2

Step-by-step explanation:

The function y=log_3 (x) passes through the point (1,0) since the function y=log_a (x) always cuts the x-axis at x = 1.

Then, if the transformed function passes through point (1,-2) then this means that the graph of y=log_3(x) was moved vertically 2 units down.

The transformation that displaces the graphically of a function k units downwards is:

y = f (x) + k

Where k is a negative number. In this case k = -2

Then the transformation is:

f(x) -2

and the transformed function is:

y = log_3 (x) -2

7 0
3 years ago
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