Use the cosine rule.
c=AB=7
b=AC=8
a=BC=3
a^2=b^2+c^2-2bc(cos(A))
=>
cos(A)=(b^2+c^2-a^2)/(2bc)
=(7^2+8^2-3^2)/(2*7*8)
=13/14
=0.9286
L = building side
W = non-building side
P = 2W + L = 42 (note only one L because the other L is the building itself)
Solve for L:
L = 42 - 2W
Area = l*w
Area = (42-2W)W = 42W - 2W2
Let area be y, so y = -2W2 +42W
Note this is a parabola pointing down because the coefficient of the W2 is negative. That makes the vertex the maximum for which we are searching.
Vertex of this parabola is at W=-b/2a, if the quadratic is aW2 + bW + c = 0
a = -2
b = 42
W = -42/(2*-2) = -42/-4 = 10.5
W = 10.5
L = 42-2(10.5) = 42-21 = 21
Area = L*W = 21 * 10.5
A = 220.5 ft2
True because the center is (2,1) and radius is 2
By the divergence theorem,

where

is the solid whose boundary is

. We have

so we set up the volume integral as

Answer: Third option

Step-by-step explanation:
The function
passes through the point (1,0) since the function
always cuts the x-axis at
.
Then, if the transformed function passes through point (1,-2) then this means that the graph of
was moved vertically 2 units down.
The transformation that displaces the graphically of a function k units downwards is:

Where k is a negative number. In this case 
Then the transformation is:

and the transformed function is:
