Question

What is the area of this parallelogram?

Answer 1

The area of this parallelogram is the sum of the area of triangle DAE , area of triangle BCF and area of rectangle DEBF

Area of trianle DAE = 1/2 * base * height = 1/2 * AE * DE = 1/2 * 4 * 7 = 14 m²

Area of trianle BCF = 1/2 * base * height = 1/2 * CF * BF = 1/2 * 4 * 7 = 14 m²

Area of rectangle DEBF = length * width = FD * DE = 8 * 7 = 56 m²

Therefore, Area of the parallelogram = 14 + 14 + 56 = 84 m²

Answer 2

A=AB*DE=(8+4)*7=12*7=84 m^2

A=84 m^2