A school gym is divided for a fair by bisecting its width and its length. Each half of the length is then bisected, forming 8 s

Question

2 years ago

11

ections in all. What are the dimensions and area of each section?

2 answers:

SVETLANKA909090 [29] · Answer 1 · 2022-06-05T03:32:13+03:00

Answer:

Dimensions will be

New Length= x/16 units

New width = y/2 units

Area=xy/32 square units

Step-by-step explanation:

Lets assume the dimensions of the school gym to be ;

Length= x

width= y

Length and width are first bisected for a fair.This means by a half

Length will be =x/2

Width will be =y/2

Then the length is divided to form 8 sections that are equal, which will ;

(x/2)÷8

x/2 * 1/8 = x/16 units

New length = x/16 units in dimension

New width will be y/2 units in dimension

Area of each section will be;

length by width

(x/16 )*(y/2)

=xy/32 square units

a_sh-v [17] · Answer 2 · 2022-06-05T05:56:28+03:00

4 0

Answer:

Each section is 22.5 ft long by 30 ft wide. The area of each section is 675 ft squared.

Step-by-step explanation:

x=60

1.5*60=90 so 90 is the length

60 is the width

90 divided by 4 is 22.5

60 divided by 2 is 30

A school gym is divided for a fair by bisecting its width and its length. Each half of the length is then​ bisected, forming 8 s