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Dimas [21]
3 years ago
5

The lengths of three sides of a quadrilateral are shown below:

Mathematics
1 answer:
sasho [114]3 years ago
7 0

Part A: To find the lengths of sides 1, 2, and 3, we need to add them together. We can do this by combining like terms (terms that have the same variables, or no variables).


(3y² + 2y − 6) + (3y − 7 + 4y²) + (−8 + 5y² + 4y)


We can now group them.


(3y² + 4y² + 5y²) + (2y + 3y + 4y) + (-6 - 7 - 8)


Now we simplify


12y² + 9y - 21


Part B: To find the length of the 4th side, we need to subtract the combined length of the 3 sides we know from the total length (perimeter).


(4y³ + 18y² + 16y − 26) - (12y² + 9y - 21)


Simplify, subtract like terms.


4y³ + (18y² - 12y²) + (16y - 9y) + (-26 + 21)


4y³ + 6y² + 7y - 5 is the length of the 4th side.


Part C (sorry for the bad explanation): A set of numbers is closed, or has closure, under a given operation if the result of the operation on any two numbers in the set is also in the set. For example, the set of real numbers is closed under addition, because adding any two real numbers results in another real number. Likewise, the real numbers are closed under subtraction, multiplication and division (by a nonzero real number), because performing these operations on two real numbers always yields another real number.

<em>Polynomials are closed under the same operations as integers. </em>

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Use the quadratic formula to solve x² + 9x + 10 = 0.<br><br> What are the solutions to the equation?
jok3333 [9.3K]

Answer:

-1.30\ and\ -7.70 (2 decimal places)

Step-by-step explanation:

Quadratic Formula: x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

-----------------------------------------------

x^2+9x+10=0

Plug in values:

x=\frac{-9\pm \sqrt{9^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}

First value of x:

x=\frac{-9+\sqrt{41}}{2}=-1.30 (2 decimal places)

Second value of x:

x=\frac{-9-\sqrt{41}}{2}=-7.70 (2 decimal places)

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