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Butoxors [25]
3 years ago
7

clark made a model of his house. his house is 30 1/2 feet long. the dimensions of the model were 1/25 the dimensions of clarks a

ctual home. what is the length, in feet of the model?​
Mathematics
1 answer:
balandron [24]3 years ago
7 0

Answer:

1.22 feet, or 1  11/50 ft

Step-by-step explanation:

Find 1/25 th of 30 1/2 feet:

 1        61 ft

----- * ---------- = 1.22 feet, or 1  11/50 ft

25      2

The length of the model is  1.22 feet, or 1  11/50 ft

You might be interested in
It is known that the life of a particular auto transmission follows a normal distribution with mean 72,000 miles and standard de
scoray [572]

Answer:

a) P(X

P(z

b) P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

P(z>-0.583)=1-P(Z

c) P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

d) z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the life of a particular auto transmission of a population, and for this case we know the distribution for X is given by:

X \sim N(72000,12000)  

Where \mu=72000 and \sigma=12000

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using excel or the normal standard table and we got:

P(z

Part b

P(X>65000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>-0.583)=1-P(Z

Part c

P(X>100000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

Part d

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

5 0
3 years ago
I need a long essay about may the bridges i burn light the way​
aivan3 [116]

Answer:

I will let it lead me down the paths ahead of me. I never in my life thought that Dylan McKay would be a major influence on my growth as a person. But that's the way it seems to be going right now. So wish me luck, and may the bridges I've burned light the way.

this is not that long but I tried

6 0
3 years ago
Which relation is also a function? {(2,0), (3,2), (2,3)} {(0,0), (3,0), (5,0)} {(3,1), (3,2), (3,3)} {(5,2), (5,4), (2,6)}
pychu [463]

Answer:

only{(0,0), (3,0), (5,0)}    (the x axis)

Step-by-step explanation:

as all the others have more than one possible output y for a unique input x

4 0
2 years ago
Write 85 expanded form
WARRIOR [948]
80 + 5 is 85 in extended form
3 0
3 years ago
Read 2 more answers
Can someone help me with this problem I really don’t know how to work it out and I’m getting frustrated please help..
11Alexandr11 [23.1K]

Answer:

  1 cake and 6 pies

Step-by-step explanation:

Let c represent the number of cakes Alice and George can make. Likewise, let p represent the number of pies.

Then the amount of flour they need (in cups) is ...

  3c + 2p . . . . cups of flour needed

And the amount of sugar needed is ...

  2c + 1.5p . . . cups of sugar needed

__

They want to use all 15 cups of flour they have, and all 11 cups of sugar, so the amounts above need to match the amounts on hand:

  3c + 2p = 15

  2c + 1.5p = 11

We can solve these equations various ways. One of my favorite is to use a graphing calculator. (See attached) It tells us that Alice and George can make 1 cake and 6 pies with the flour and sugar they have.

_____

If you want to solve these equations algebraically, there are several methods for that, too. Here, we can multiply the first one by 2/3 and subtract the result from the second one:

  (2c +1.5p) -(2/3)(3c +2p) = (11) -(2/3)(15)

  2c +3/2p -2c -4/3p = 11 -10 . . . . . eliminate parentheses

  1/6p = 1 . . . . . . . . . . . . . . . . . . . . . .collect terms

  p = 6 . . . . . . . . . . . . . . . . . . . . . . . . multiply by 6

Substituting into the first equation gives ...

  3c +2·6 = 15 . . . substitute 6 for p

  3c = 3 . . . . . . . . subtract 12

  c = 1 . . . . . . . . . . divide by 3

These values tell us Alice and George can make 1 cake and 6 pies with the flour and sugar they have.

7 0
3 years ago
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