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Annette [7]
2 years ago
12

The recangle is 23 ft long and 14ft wide if the Gardner wants to build a fence around the garden, how many feet of fence is requ

ired
Mathematics
1 answer:
MAVERICK [17]2 years ago
3 0
The answer is 106.83 i hope it helps 
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I will give brainliest here is the picture I need this ASAP
julia-pushkina [17]

Answer:

Step-by-step explanation:

Start with our equation:

s=2(lw+wh+hl)

Plug in our values for l, w, and h:

s=2(12*9+9*2+2*12)

Simplify:

s=300

7 0
3 years ago
Football fields are 360 ft in length and 160 ft in width. Find the area
rjkz [21]

Answer:

57600cm^2

Step-by-step explanation:

To find the area, you do length * width. In this case, you do 360 * 160. The output will then be 57600cm^2

7 0
3 years ago
Read 2 more answers
Write down the value of the 7 in the number 5709.​
Dovator [93]

Answer:

700

Step-by-step explanation:

The 9 = 9

The 0 = 0

The 7 = 700

The 5 = 5000

8 0
3 years ago
Find the length of the third side to the nearest tenth<br> 7<br> 1
AlexFokin [52]

Answer:

10.7

Step-by-step explanation:

3 0
3 years ago
1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)
Sveta_85 [38]

Answer:

1. -5x+3y+44=0

2. 2x+y-2=0

3. 2x+y-4=0

Step-by-step explanation:

Standard form of a line is Ax+By+C=0.

If a line passing through two points then the equation of line is

y-y_1=m(x-x_1)

where, m is slope, i.e.,m=\dfrac{y_2-y_1}{x_2-x_1}.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)

y+3=\dfrac{-5}{-3}(x-7)

y+3=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

-5x+3y+9+35=0

-5x+3y+44=0

Therefore, the required equation is -5x+3y+44=0.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

Slope of the line : m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

y-2=-2(x-0)

y-2=-2x

2x+y-2=0

Therefore, the required equation is 2x+y-2=0.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y =-5.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

y-0=-2(x-2)

y=-2x+4

2x+y-4=0

Therefore, the required equation is 2x+y-4=0.

5 0
3 years ago
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