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AnnZ [28]
3 years ago
12

Add the following polynomials:

Mathematics
2 answers:
JulijaS [17]3 years ago
8 0
Add:  <span>(−x^3 + 26x^2 − 7x − 13) + (6x^4 − x^3 +8x + 27)

You may find it easier to write these one above the other:

</span><span>             (−x^3 + 26x^2 − 7x − 13)
+ (6x^4 − x^3               +8x + 27)
-------------------------------------------
 6x^4    -2x^3  + 26x^2   +x   + 14   (answer)

Please note:  You should use " ^ " to indicate exponentation.
</span><span>6x4 −2x3 + 26x2 +x + 14     NO
</span><span>6x4 −2x^3 + 26x^2 +x + 14    YES

</span>
alekssr [168]3 years ago
6 0

Answer:

is the answer 11?

Step-by-step explanation:


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If the mean of A and B is 20, the mean of B and C is 24 and the mean of A,B and C is 18.What is the mean of A and C?
Zielflug [23.3K]

Answer:

the mean of A and C is 10

Step-by-step explanation:

Given;

mean of A and B = 20

mean of B and C = 24

mean of A, B and C = 18

\frac{A + B}{2} = 20\\\\A+ B = 40 ---- (1)\\\\\frac{B + C}{2} = 24\\\\B+ C = 48----(2)\\\\\frac{A+ B+ C}{3} = 18\\\\A+ B+ C= 54---(3)\\\\From (1); \ A = 40 - B\\\\From(2); \ C = 48 - B\\\\\Substitute \ the \ values \ of \ A \ and \ C \ into \ (3)\\\\(40-B) + B + (48-B) = 54\\\\simplify;\\\\(40 + 48) + (B-B-B)= 54\\\\88 -B = 54\\\\-B = 54-88\\\\-B = -34\\\\B = 34

Recall; A = 40 - B

           A = 40 - 34

           A = 6

Also, C = 48 - B

        C = 48 - 34

       C = 14

Therefore, the mean of A and C is calculated as;

= \frac{A + C}{2} \\\\= \frac{6 + 14}{2} \\\\= 10

5 0
3 years ago
Answer quick please: Evaluate the expression...I forgot how to do the negatives..and I literally was just doing them yesterday..
nekit [7.7K]
(7.5 x 10^-3) + (5.8 x 10^-3 )

= (7.5 x 1/1000) + (5.8 x 1/1000) OR decimal form  --> (7.5 x 0.001) +(5.8 x 0.001)

0.0075 + 0.0058 = 3/400+29/5000

0.0133 = 133/10000 

Hope it helps. 


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Answer:

Easy

Step-by-step explanation:

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