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Ratling [72]
3 years ago
12

Darnay deposited $10 in a saving account earring 10% interest compound annually to the nearest cent how much will he have in 3 y

ears
Mathematics
2 answers:
loris [4]3 years ago
8 0
$10 x 1.1 x 1.1 x 1.1 = $13.31
Angelina_Jolie [31]3 years ago
7 0
10×(1+0.1)^(3)
=13.31
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How many sixteenth notes would be needed to have the same duration as 3 quarter notes? Represent this as a fraction
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Fred the Flying Fish can fly further than any other fish.He even holds the world record for longest flight by a fish! Fred’s pre
Ilia_Sergeevich [38]
.196 minutes long is the answer
5 0
3 years ago
Read 2 more answers
Help me please and thank you
Fittoniya [83]

There are 650 toothpicks in a regular sized box.

That is the volume of the box = 650 toothpicks

Jumbo box is made by doubling all the dimensions.

We know volume = length * width * height = L*W*H

We double all the dimensions for Jumbo box

L becomes 2L

W become 2W

H becomes 2H

Volume of Jumbo box = 2L * 2W * 2H = 8*L*W*H

Volume of jumbo box = 8 * volume of small box

= 8 * 650= 5200

The Jumbo box holds 5200 toothpicks .

7 0
3 years ago
How does the sample size affect the validity of an empirical​ argument? A. The larger the sample size the better. B. The smaller
astra-53 [7]

Answer:

A. The larger the sample size the better.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

We have to look at the standard error, which is:

s = \frac{\sigma}{\sqrt{n}}

This means that an increase in the sample size reduces the standard error, and thus, the larger the sample size the better, and the correct answer is given by option a.

7 0
3 years ago
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