Answer: 5 and 6
Step-by-step explanation:
sqrt1=1
sqrt4=2
sqrt9=3
sqrt16=4
sqrt25=5
sqrt29~5.4
sqrt36=6
Comment
You can't get to quadrant 4 to quad 2 without 2 steps. The answers tell you that. The question is, did you use a reflection and a y or x translations or 2 reflections or 2 y or 2x translations.
Argument
You can take one point and see if it translate from beginning (purple triangle) to (yellow triangle) end. If two conditions will get you the right answer, then you have to try another point to break the tie.
We'll use Point C.
Choice A: If you reflect C over the y axis, you will go from (-5,1) to (5,1)
If you move C six units down, you will go from (5,1) to (5,-5) which is where C' is.
That is pretty much the answer.
I could confirm it with another point which is the way your should do it.
Try Point A
Choice A: Point A reflects across the y axis going from (-3,4) to (3,4)
Point A translates down by moving from (3,4) to (3,-2) to become A'
Answer reflection and translation in condition A
More Comment
I should do one more for you to show you that it is wrong.
You can try Choice B of the multiple Choice answers.
We will use Point C
If we translate C across the x axis it will go from (-5,1) to (-5,-1)
The we are to translate 1 unit up. We will go from (-5,0) from (-5,-1) That's nowheres near where C' is. Choice B is wrong.
This is a simple equation:
x - 7 < 14
x < 14 + 7
x < 21
→ Many people think that because there is not "=" sign they don't flip the sign of what in this case is -7. But actually, the symbols "<" and ">" act as the equal sign. This rule doesn't apply to positive number, only negative.
Hope it helped,
BioTeacher101
(If you have any questions, feel free to ask them in the comments)
\left[x \right] = \left[ \frac{13}{6}\right][x]=[613]
totally answer
Answer:
x<6/5, x>14/5
Step-by-step explanation:
Steps
$5\left|x-2\right|+4>8$
$\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}$
$5\left|x-2\right|+4-4>8-4$
$\mathrm{Simplify}$
$5\left|x-2\right|>4$
$\mathrm{Divide\:both\:sides\:by\:}5$
$\frac{5\left|x-2\right|}{5}>\frac{4}{5}$
$\mathrm{Simplify}$
$\left|x-2\right|>\frac{4}{5}$
$\mathrm{Apply\:absolute\:rule}:\quad\mathrm{If}\:|u|\:>\:a,\:a>0\:\mathrm{then}\:u\:<\:-a\:\quad\mathrm{or}\quad\:u\:>\:a$
$x-2<-\frac{4}{5}\quad\mathrm{or}\quad\:x-2>\frac{4}{5}$
Show Steps
$x-2<-\frac{4}{5}\quad:\quad x<\frac{6}{5}$
Show Steps
$x-2>\frac{4}{5}\quad:\quad x>\frac{14}{5}$
$\mathrm{Combine\:the\:intervals}$
$x<\frac{6}{5}\quad\mathrm{or}\quad\:x>\frac{14}{5}$
