16:24 students made at least 80% on the test. The question is what is the ratio of students who scored below an 80% to the total number of students. 8:24 would be the right answer, but since it is asking for the answer in the simplest form, it would be 1:3.
Answer:
The answer is C=6p3 + 29p2 + 22p – 21
Step-by-step explanation:
To calculate the product, we need to multiply each member of each multiplier:
(2p + 7)(3p2 + 4p – 3) = 2p · 3p² + 2p · 4p + 2p · -3 + 7 ·3p² + 7 · 4p + 7 · -3
= 6p³ + 8p² - 6p + 21p² + 28p - 21
= 6p³ + 8p² + 21p² + 28p - 6p -21
= 6p³ + 29p² + 22p - 21
Therefore, the product of (2p + 7)(3p2 + 4p – 3) is 6p³ + 29p² + 22p -21
Answer: b) multiply row 1 by -3 and add the result to row 2
Step-by-step explanation:
Answer:
Step-by-step explanation:
You have no grounds for making a statement like that. There are a variety of reasons why you might not get immediate answers. Be patient.
I will do the second part of this question (finding the first three numbers):
a(4) = a(3)*(-3) + 2 = -148, so a(3)*(-3) = -150 and a(3) = -50
a(3) = 50
a(2) = a(3)*(-3) + 2 = 50, so -3*a(3) = 48 and a(d) = -16
a(1) = a(2)*(-3) + 2 = -16, so a(2)*(-3) = -18 and a(1) = 6
The procedure for finding a(5), a(6) and a(7) is exactly the same.
complette the square to get vertex form or y=a(x-h)^2+k
(h,k) is vertex
1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
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2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
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3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
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4. complete the squre and expand
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so
y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)