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Andre45 [30]
2 years ago
9

Graph the solution set to this inequality. -2x+9_> 5x-12

Mathematics
1 answer:
Vedmedyk [2.9K]2 years ago
5 0

x ≤  3 (closed dot going to the left)

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Which of the following equations describes the graph shown above
andrey2020 [161]

Answer: D

Step-by-step explanation:

this is in y=Mx+ b form. M stands for the slope and b stands for the y intercept, or where the line intersects with the y-axis.

Going left to right, the line slopes downwards, therefore it is a negative Slope. This narrows down your answer to either a or d. the slope is -1 because you can only ever write x by itself if it means 1x. In this case it is negative so it would look like this: -x

for the y-intercept, simply look at where the line passes through the y-axis. In this case, it is positive 2.

your finished equation would be: y=-x+2

i hope this is helpful

8 0
2 years ago
What is the value of each expression in the simplest form? -11/15 + (-2/15)
Liula [17]

Answer:

\frac{ - 13}{15}

Step-by-step explanation:

\frac{ - 11}{15}  +  \frac{ - 2}{15}  =  \frac{( - 11 - 2)}{15}  =   \frac{ - 13}{15}

6 0
2 years ago
Which algebraic expression is equivalent to this expression 6(3x+5)-20
Ksju [112]
18x+10. I used the distributive property and then combined like terms. Please let me know if you want me to explain further!
7 0
3 years ago
Please help asap!!!!
Leya [2.2K]

Answer:

z = 25

Step-by-step explanation:

adjacent angles in a rhombus are supplementary

3z - 15 + 7z - 55 = 180

10z - 70 = 180

10z = 250

z = 25

6 0
2 years ago
If the term of arthematic progression decrease in magnitude then common difference must be
Tpy6a [65]

We can say that if the term of arithmetic progression decrease in magnitude then the common difference must be <u>negative</u>.

An arithmetic progression is a sequence where every term is a sum of the previous term and a common difference.

If we suppose the first term of an arithmetic progression to be a, and the common difference to be d, then the arithmetic progression goes like this:

The first term, a₁ = a,

Second term, a₂ = a₁ + d = a + d,

Third term, a₃ = a₂ + d = a + 2d,

Fourth term, a₄ = a₃ + d = a + 3d, and it goes so on up to,

The n-th term, aₙ = aₙ₋₁ + d = a + (n - 1)d.

In the question, we are asked if the term of arithmetic progression decrease in magnitude then what can we say about the common difference.

As the magnitude of the term decreases, we can show that as:

The n-th term < The first term,

or, aₙ < a₁,

or, a + (n - 1)d < a,

or, a + (n - 1)d - a < a - a {Subtracting a from both sides},

or, (n - 1)d < 0.

Since, n > 1, (n - 1) > 0, thus we get the common difference, d < 0, that is, the common difference is negative.

Thus, we can say that if the term of arithmetic progression decrease in magnitude then the common difference must be <u>negative</u>.

Learn more about arithmetic progressions at

brainly.com/question/6561461

#SPJ4

8 0
2 years ago
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