1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
krek1111 [17]
3 years ago
14

What is 23 divided by 184

Mathematics
2 answers:
Nonamiya [84]3 years ago
6 0
8.......................................................................
Travka [436]3 years ago
5 0
0.125 would be your answer! (:
You might be interested in
A pair of Jeans has a marked price AED 800.
Bumek [7]

Answer:

640

Step-by-step explanation:

you say 100% = 800

what about 80%(i get 80% after substracting 100% that's marked price - 20% discount)

then u say 80×800÷100

4 0
3 years ago
Can someone plz help ASAP this is confusing
mr_godi [17]

Answer:

third option

Step-by-step explanation:

four times a number: 4n

add 8 to it: 4n + 8

All of this equals to -12.

Hence: 4n + 8 = -12

6 0
3 years ago
Read 2 more answers
99 POINT QUESTION, PLUS BRAINLIEST!!!
VladimirAG [237]
First, we have to convert our function (of x) into a function of y (we revolve the curve around the y-axis). So:


y=100-x^2\\\\x^2=100-y\qquad\bold{(1)}\\\\\boxed{x=\sqrt{100-y}}\qquad\bold{(2)} \\\\\\0\leq x\leq10\\\\y=100-0^2=100\qquad\wedge\qquad y=100-10^2=100-100=0\\\\\boxed{0\leq y\leq100}

And the derivative of x:

x'=\left(\sqrt{100-y}\right)'=\Big((100-y)^\frac{1}{2}\Big)'=\dfrac{1}{2}(100-y)^{-\frac{1}{2}}\cdot(100-y)'=\\\\\\=\dfrac{1}{2\sqrt{100-y}}\cdot(-1)=\boxed{-\dfrac{1}{2\sqrt{100-y}}}\qquad\bold{(3)}

Now, we can calculate the area of the surface:

A=2\pi\int\limits_0^{100}\sqrt{100-y}\sqrt{1+\left(-\dfrac{1}{2\sqrt{100-y}}\right)^2}\,\,dy=\\\\\\= 2\pi\int\limits_0^{100}\sqrt{100-y}\sqrt{1+\dfrac{1}{4(100-y)}}\,\,dy=(\star)

We could calculate this integral (not very hard, but long), or use (1), (2) and (3) to get:

(\star)=2\pi\int\limits_0^{100}1\cdot\sqrt{100-y}\sqrt{1+\dfrac{1}{4(100-y)}}\,\,dy=\left|\begin{array}{c}1=\dfrac{-2\sqrt{100-y}}{-2\sqrt{100-y}}\end{array}\right|= \\\\\\= 2\pi\int\limits_0^{100}\dfrac{-2\sqrt{100-y}}{-2\sqrt{100-y}}\cdot\sqrt{100-y}\cdot\sqrt{1+\dfrac{1}{4(100-y)}}\,\,dy=\\\\\\ 2\pi\int\limits_0^{100}-2\sqrt{100-y}\cdot\sqrt{100-y}\cdot\sqrt{1+\dfrac{1}{4(100-y)}}\cdot\dfrac{dy}{-2\sqrt{100-y}}=\\\\\\

=2\pi\int\limits_0^{100}-2\big(100-y\big)\cdot\sqrt{1+\dfrac{1}{4(100-y)}}\cdot\left(-\dfrac{1}{2\sqrt{100-y}}\, dy\right)\stackrel{\bold{(1)}\bold{(2)}\bold{(3)}}{=}\\\\\\= \left|\begin{array}{c}x=\sqrt{100-y}\\\\x^2=100-y\\\\dx=-\dfrac{1}{2\sqrt{100-y}}\, \,dy\\\\a=0\implies a'=\sqrt{100-0}=10\\\\b=100\implies b'=\sqrt{100-100}=0\end{array}\right|=\\\\\\= 2\pi\int\limits_{10}^0-2x^2\cdot\sqrt{1+\dfrac{1}{4x^2}}\,\,dx=(\text{swap limits})=\\\\\\

=2\pi\int\limits_0^{10}2x^2\cdot\sqrt{1+\dfrac{1}{4x^2}}\,\,dx= 4\pi\int\limits_0^{10}\sqrt{x^4}\cdot\sqrt{1+\dfrac{1}{4x^2}}\,\,dx=\\\\\\= 4\pi\int\limits_0^{10}\sqrt{x^4+\dfrac{x^4}{4x^2}}\,\,dx= 4\pi\int\limits_0^{10}\sqrt{x^4+\dfrac{x^2}{4}}\,\,dx=\\\\\\= 4\pi\int\limits_0^{10}\sqrt{\dfrac{x^2}{4}\left(4x^2+1\right)}\,\,dx= 4\pi\int\limits_0^{10}\dfrac{x}{2}\sqrt{4x^2+1}\,\,dx=\\\\\\=\boxed{2\pi\int\limits_0^{10}x\sqrt{4x^2+1}\,dx}

Calculate indefinite integral:

\int x\sqrt{4x^2+1}\,dx=\int\sqrt{4x^2+1}\cdot x\,dx=\left|\begin{array}{c}t=4x^2+1\\\\dt=8x\,dx\\\\\dfrac{dt}{8}=x\,dx\end{array}\right|=\int\sqrt{t}\cdot\dfrac{dt}{8}=\\\\\\=\dfrac{1}{8}\int t^\frac{1}{2}\,dt=\dfrac{1}{8}\cdot\dfrac{t^{\frac{1}{2}+1}}{\frac{1}{2}+1}=\dfrac{1}{8}\cdot\dfrac{t^\frac{3}{2}}{\frac{3}{2}}=\dfrac{2}{8\cdot3}\cdot t^\frac{3}{2}=\boxed{\dfrac{1}{12}\left(4x^2+1\right)^\frac{3}{2}}

And the area:

A=2\pi\int\limits_0^{10}x\sqrt{4x^2+1}\,dx=2\pi\cdot\dfrac{1}{12}\bigg[\left(4x^2+1\right)^\frac{3}{2}\bigg]_0^{10}=\\\\\\= \dfrac{\pi}{6}\left[\big(4\cdot10^2+1\big)^\frac{3}{2}-\big(4\cdot0^2+1\big)^\frac{3}{2}\right]=\dfrac{\pi}{6}\Big(\big401^\frac{3}{2}-1^\frac{3}{2}\Big)=\boxed{\dfrac{401^\frac{3}{2}-1}{6}\pi}

Answer D.
6 0
3 years ago
Read 2 more answers
X^3 - 2y^2 - 3x^3 + z^4
Andreyy89

Answer:

-2x³ - 2y² + z⁴

Step-by-step explanation:

Step 1: Write out expression

x³ - 2y² - 3x³ + z⁴

Step 2: Combine like terms (x³)

-2x³ - 2y² + z⁴

8 0
3 years ago
Alana practice dancing 11/4 hours on Monday 19/8 hours on Wednesday and 2.6 hours on Friday on which day did she practice the cl
liubo4ka [24]

Answer:

On Wednesday

Step-by-step explanation:

In this question, We have Alana practicing for three days. We now need to know in which of the days has she practiced closest to 2 hours. Hence, what we are to do here is simply find which of the practicing hours is nearest to 2hours.

The best thing to do here is to work with minutes. Hence whatsoever fraction we are having would be worked with based on minutes. Let’s do this!

On Monday, she practiced 11/4 hours. This means she practiced 11/4 * 60 minutes = 165 minutes

On Tuesday, practice was for 19/8 hours. This means she had practiced for 19/8 *60 = 142.5 minutes

Lastly, on Wednesday, her practice time was 2.6 hours and that is 2.6 * 60 = 156 minutes

Kindly note that 2 hours is same as 120 minutes. We just need to know which of these minutes is closest to 120 minutes. From what we have, 142.5 is the closest.

This means that her practice on Wednesday is the closest to two hours.

4 0
3 years ago
Read 2 more answers
Other questions:
  • There are eight volunteers at the election. The goal for the evening is to raise $952. If each volunteer raises the same amount,
    14·2 answers
  • The circular bases of the traditional teepees of the Sioux and Cheyenne tribes have a diameter of about 15 ft. What is the area
    11·1 answer
  • Find the slope of the line through each pair of points (-12,0) (20,0)
    11·1 answer
  • The scale on a map of Indiana is 1 inch=42 miles jill measured the distance on the map from the eastern border to the western bo
    7·1 answer
  • Can someone plz help me with number 6 I’m not under stand this show work plzz
    8·2 answers
  • The volume Vr (in cubic meters) of a spherical balloon with radius r meters is given by =Vr43πr3. The radius Wt (in meters) afte
    11·1 answer
  • I need help on this math problem.
    13·1 answer
  • Which statement is true
    15·2 answers
  • A perfect square is the product of any positive whole number used as a factor exactly two times. [Example: 49 is a perfect squar
    8·2 answers
  • Only answer the following: Fill in the graph. 2: part b. And 3.
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!