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julia-pushkina [17]
3 years ago
8

Can someone plz help me with number 6 I’m not under stand this show work plzz

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
7 0

Check the picture below.

MatroZZZ [7]3 years ago
3 0

Answer:

Step-by-step explanation:

P = 9x + 6 + x + 18 + 2x + 23 + 7x - 2 = 19x + 45.

2x + 23 = 7x - 2

   5x = 25

   x = 5

Therefore P = (19)(5) + 45 = 140.

EF = 23, FG = 51, EG = 66.

1) It is a scalene triangle.

2) Angle FEH is acute.

Let a = angle FEH:

23^2 + 66^2 - 2*23*66*cos(a) = 51^2

cos(a) = (23^2 + 66^2 - 51^2)/(2*23*66), which is a positive value, thus a is an acute angle.

3) angle EFG is obtuse.

Let x = angle EFG:

23^2 + 51^2 - 2*23*51*cos(x) = 66^2

(23^2 + 51^2 - 66^2)/(2*23*51) = cos(x)

cos(x) = a negative value, thus x is obtuse.

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The first term of an AP is -7 and the ratio of the eight term to the third term is 7:1 calculate the common difference
alukav5142 [94]

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the common difference is 6.

Step-by-step explanation:

Given;

first term of an AP, a = -7

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The eight term is written as;

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The ratio of the eight term to third term = 7:1

\frac{T_8}{T_3} = \frac{7}{1} = \frac{a+ 7d}{a + 2d} \\\\7 =  \frac{a+ 7d}{a + 2d}\\\\Recall, a = -7\\\\7 =   \frac{-7+ 7d}{-7 + 2d}\\\\7(-7 + 2d) = -7+ 7d\\\\-49 + 14d = -7 + 7d\\\\14d -7d = -7 + 49\\\\7d = 42\\\\d = \frac{42}{7} \\\\d = 6

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