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3 years ago

Help plz math related question

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

5 0

B hope this helps. .......................

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The two intervals (114.9, 115.7) and (114.6, 116.0) are confidence intervals (computed using the same sample data) for μ = true

kenny6666 [7]

Answer:

115.3 hertz

Step-by-step explanation:

For either interval, the value of the sample mean is given by the average of the lower and upper bound of the confidence interval. Since both intervals were constructed by using the same sample, both values should be equal.

For the first interval:

$M=\frac{114.9 + 115.7}{2} \\M=115.3\ hertz$

For the second interval:

$M=\frac{114.6 + 116.0}{2} \\M=115.3\ hertz$

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3 years ago

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Answer: 13 units

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butalik [34]

Answer:

Step-by-step explanation:

1.2 x 3.7 nearest tenth

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3 years ago

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Find the value of annuity if the periodic deposit is $250 at 5% compounded quarterly for 10 years

mylen [45]

Answer:

The value of annuity is $P_v = \$ 7929.9$

Step-by-step explanation:

From the question we are told that

The periodic payment is $P = \$ 250$

The interest rate is $r = 5\% = 0.05$

Frequency at which it occurs in a year is n = 4 (quarterly )

The number of years is $t = 10 \ years$

The value of the annuity is mathematically represented as

$P_v = P * [1 - (1 + \frac{r}{n} )^{-t * n} ] * [\frac{(1 + \frac{r}{n} )}{ \frac{r}{n} } ]$ (reference EDUCBA website)

substituting values

$P_v = 250 * [1 - (1 + \frac{0.05}{4} )^{-10 * 4} ] * [\frac{(1 + \frac{0.05}{4} )}{ \frac{0.08}{4} } ]$

$P_v = 250 * [1 - (1.0125 )^{-40} ] * [\frac{(1.0125 )}{0.0125} ]$

$P_v = 250 * [0.3916 ] * [\frac{(1.0125)}{0.0125} ]$

$P_v = \$ 7929.9$

8 0

3 years ago