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notsponge [240]
3 years ago
6

How many pairs of whole numbers equal sum of 40

Mathematics
1 answer:
Flura [38]3 years ago
3 0
There are at least 20 pairs of whole numbers that are equal to the sum of 40. I will list them for you~
1+39=40
2+38= 40
3+37=40 
4+36= 40
5+35=40 
6+34=40
7+33=40
8+32=40
9+31= 40
10+30=40
11+29=40
12+28=40 
13+27= 40 
14+26=40 
15+25=40 
16+ 24= 40 
17+23= 40 
8+ 22= 40 
19+21=40 
<span>20+20= 40 
</span>Here you go, hoped this has helped in any sort of way~
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<h3>What is the cost of painting the rooms?</h3>

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Answer:

Step-by-step explanation:

Let the quadratic equation of the function by the points in the given equation is,

f(x) = ax² + bx + c

If the points lying on the graph are (-3, -10), (-4, -8) and (0, 8),

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f(-4) = a(-4)² + b(-4) + 8

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Subtract equation (1) from equation (2)

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From equation (1),

6 - b = -6

b = 12

Function will be,

f(x) = 2x² + 12x + 8

     = 2(x² + 6x) + 8

     = 2(x² + 6x + 9 - 9) + 8

     = 2(x² + 6x + 9) - 18 + 8

     = 2(x + 3)² - 10

By comparing this function with the vertex form of the function,

y = a(x - h)² + k

where (h, k) is the vertex.

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And axis of symmetry will be,

x = -3

From the given graph, axis of the symmetry of the function 'g' is; x = -3

Therefore, both the functions will have the same axis of symmetry.

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Therefore, y-intercept of 'f' is greater than 'g'

Average rate of change of function 'f' = \frac{f(b)-f(a)}{b-a} in the interval [a, b]

                                                               = \frac{f(-3)-f(-6)}{-3+6}

                                                               = \frac{-10-8}{3}

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Average rate of change of function 'g' = \frac{g(b)-g(a)}{b-a}

                                                                = \frac{g(-3)-g(-6)}{-3+6}

                                                                = \frac{7+2}{-3+6}

                                                                = 3

Therefore, Average rate of change of function 'f' is less than 'g'.

6 0
3 years ago
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