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jenyasd209 [6]
3 years ago
13

Calculus1 help involving graphs.

Mathematics
1 answer:
tatuchka [14]3 years ago
4 0

Answer:

-0.67

Step-by-step explanation:

Pick two points on the tangent line, and find the slope between them.

The line passes through approximately (30,145) and (90, 105).

m = (105 − 145) / (90 − 30)

m = -0.67

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1 5 ? whats the missing number?<br> _ + _= _<br> 9 6 18
Gnesinka [82]

Answer:

17 / 18

Step-by-step explanation:

1/9 + 5/6 needs to be converted to a different equivalent fraction so that the denominators are the same, so;

1/9 = 2/18 and 5/6 = 15/18

2/18 + 15/18 = 17/18!

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If the price of a purse went from $45 to $54, what was the percent of the change?
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3 years ago
Help me pleaseee (10 points )
Gemiola [76]

Answer:

m<T = , m<M =  and m<Z =

Step-by-step explanation:

From the given ∆TMZ, let the measure angle T be represented by T.

So that,

m<M = 2T + 6°

m<Z = 5T - 50°

Sum of angles in a triangle =

T + (2T + 6°) + (5T - 50°) =

8T - =

8T =  +

   =

T =

  =

Therefore,

i. m<T =

ii. m<M = 2T + 6°

       = 2 x  + 6°

       =

m<M =

iii. m<Z = 5T - 50°

           = 5 x  - 50°

           =  - 50°

           =

m<Z =

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Find the surface area of the figure. For calculations involving , give both the exact value and an approximation to the nearest
leva [86]
Where is the picture?
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Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children
Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

p = 0.69

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}

0.07\sqrt{n} = 1.2996

\sqrt{n} = \frac{1.2996}{0.07}

\sqrt{n} = 18.5658

(\sqrt{n})^{2} = (18.5658)^{2}

n = 345

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0
3 years ago
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