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kirill [66]
2 years ago
8

An object is acted upon by the forces F1=<10​,6​,4> and F2=<0​,3​,9>. Find the force F3 that must act on the object

so that the sum of the forces is zero.
Mathematics
1 answer:
murzikaleks [220]2 years ago
8 0

\vec F_3=\langle x,y,z\rangle is a force vector such that

\vec F_1+\vec F_2+\vec F_3=\vec0

\implies\langle10,6,4\rangle+\langle0,3,9\rangle+\langle x,y,z\rangle=\langle0,0,0\rangle

\implies\begin{cases}10+x=0\\9+y=0\\13+z=0\end{cases}\implies x=-10,y=-9,z=-13

So the missing force is

\boxed{\vec F_3=\langle-10,-9,-13\rangle}

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Answer:

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Step-by-step explanation:

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3 years ago
I'm an integer. I am less than zero but greater than -13. When you subtract me from -11. The result is positive. What number am
harina [27]

<u>Answer</u><u>: </u>

Required integer is -12.

Step-by-step explanation:

Given:

Required number is integer.

Required integer is less than zero

greater than -13.

When number is substracted from -11, result is positive.

To Find:

The integer=?

Solution:

Lets assume required integer = x

As Required integer is less than zero and greater than -13 ,  

-13 < x < 0     ------(1)

Also when number is subtracted from -11, result is positive.  

=>  -11 – x > 0

=> -11 > x   -------(2)  

So form 1 and 2  

-13 < x < -11 that is x is an integer which is less than -11 and greater than -13.  There is only one integer between -13 and -11 that is -12.

Hence required integer is -12.

4 0
3 years ago
Needs help with this!!!
barxatty [35]

Answer:

y^1=-1(x-1)+(1+9)

Step-by-step explanation:

y=-1x+1\ \ == > \ \ y^1=-1(x-1)+(1+9)

-1 horizontally = 1 units left (the x-axis)

9 vertically = 9 units up (y-axis)

*Black line: is the preimage

*Red line is the translation

Hope this helps!

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2 years ago
In the right triangle shown, what is the value of x (to the nearest tenth)?
AVprozaik [17]
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4 0
3 years ago
Read 2 more answers
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