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Goryan [66]
3 years ago
12

The points (4, 9) and (0, 0) fall on a particular line. What is its equation in slope-intercept form?

Mathematics
1 answer:
Nikolay [14]3 years ago
5 0

Answer:

The equation of the line would be y = 4/9x

Step-by-step explanation:

In order to find the equation, we first need to find the slope. We can do this by using the slope equation with the points.

m(slope) = (y2 - y1)/(x2 - x1)

m = (9 - 0)/(4 - 0)

m = 9/4

Now that we have this, we can use point-slope form along with one of the points to get the equation.

y - y1 = m(x -x1)

y - 0 = 4/9(x - 0)

y = 4/9x

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\sqrt{5x} + √6 = √9


The first step is to get \sqrt{5x} by itself. We can do this by subtracting \sqrt{6} from each side, and simplifying \sqrt{9}


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Using the formula (a - b)² = a² -2ab + b², (3 - \sqrt{6})² = 15 - 6\sqrt{6}


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Step-by-step explanation:

To find the x coordinate of the midpoint, take the x coordinates of the endpoints, add them and divide by 2

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