Answer:
A. Slope = 4 and y-intercept = 3
Sam divided a rectangle into 8 congruent rectangles that each have a area of 5 cm2. what is the area of the rectangle before it is divided?
Answer:
Step-by-step explanation:
Given:
Sam divided a rectangle into 8 congruent rectangles that each have an area of 
We need to find the area of the rectangle before Sam divided it.
The area of the rectangle before Sam divided is 8 times of the area of the congruent rectangles.
Area of the rectangle = 
Area of the congruent rectangle is
So the area of the rectangle is
Area of the rectangle = 
Area of the rectangle = 
Therefore the area of the rectangle before divided is
Answer: Subtract 6 from both sides. Then, one would get 3x=15. Divde by 3 on both sides. x=5.
Step-by-step explanation:
True
Solution,5X-4.3-3X =5.7
or,5X-3X=5.7+4.3
or ,2X=10
or,X=10/2
or,X=5
Answer:
309 students
Step-by-step explanation:
Out of 600 students who complete the proficiency test, 423 were found to be proficient in reading, 398 were found to be proficient in math, and 512 were found to be proficient in either reading or math. How many were proficient in both reading and math?
We solve the above question using the formula below:
Where R = Proficiency in reading
M = Proficiency in maths
n ( R ∪ M) = n(R) + n ( M) - n ( R ∩ M)
n ( R ∪ M) = 512 students
n(R) = 423
n ( M) = 398
n ( R ∩ M) = ??
Hence:
512 = 423 + 398 - n ( R ∩ M)
n ( R ∩ M) = 423 + 398 - 512
= 821 - 512
= 309
The number of people proficient in both reading and math [n ( R ∩ M)] = 309 students
