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2 years ago

Is this righttt???? Huh

Mathematics

2 answers:

oksano4ka [1.4K]2 years ago

6 0

Answer:

Should be!!! i remember taking that quiz but i dont really remember

Step-by-step explanation:

Volgvan2 years ago

3 0

Step-by-step explanation:

yeah Siginor you are absolutely bang on target!

hope you might be helped !

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A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s heigh

Nataly_w [17]

Answer D). 9 ft is correct

Height of the ball at a horizontal distance of 10 feet is 9 ft

Step-by-step explanation:

A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s height (y).

Y(x) = $-0.02x^{2} +0.8x+3$

Question asked is " What will be height (Y) of the ball when X=10 ft "

Simply putting value of X in given equation

we get,

Y(x) = $-0.02x^{2} +0.8x+3$

Y(x) = $-0.02(10)^{2} +0.8(10)+3$

Y(x) = $-0.02(100)} +8+3$

Y(x) = $-2 +8+3$

Y(x) = $9$

Therefore, Height of the ball at a horizontal distance of 10 feet is 9 ft

Answer D. 9 ft is correct

6 0

3 years ago

I will give brainiest

lesya692 [45]

Answer:

B. {1, -4}

Step-by-step explanation:

Just rotate the screen and look at the position.

4 0

2 years ago

Find the arc length of the given curve between the specified points. x = y^4/16 + 1/2y^2 from (9/16), 1) to (9/8, 2).

lutik1710 [3]

Answer:

The arc length is $\dfrac{21}{16}$

Step-by-step explanation:

Given that,

The given curve between the specified points is

$x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}$

The points from $(\dfrac{9}{16},1)$ to $(\dfrac{9}{8},2)$

We need to calculate the value of $\dfrac{dx}{dy}$

Using given equation

$x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}$

On differentiating w.r.to y

$\dfrac{dx}{dy}=\dfrac{d}{dy}(\dfrac{y^2}{16}+\dfrac{1}{2y^2})$

$\dfrac{dx}{dy}=\dfrac{1}{16}\dfrac{d}{dy}(y^4)+\dfrac{1}{2}\dfrac{d}{dy}(y^{-2})$

$\dfrac{dx}{dy}=\dfrac{1}{16}(4y^{3})+\dfrac{1}{2}(-2y^{-3})$

$\dfrac{dx}{dy}=\dfrac{y^3}{4}-y^{-3}$

We need to calculate the arc length

Using formula of arc length

$L=\int_{a}^{b}{\sqrt{1+(\dfrac{dx}{dy})^2}dy}$

Put the value into the formula

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4}-y^{-3})^2}dy}$

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-2\times\dfrac{y^3}{4}\times y^{-3}}dy}$

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-\dfrac{1}{2}}dy}$

$L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4})^2+(y^{-3})^2+\dfrac{1}{2}}dy}$

$L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4}+y^{-3})^2}dy}$

$L= \int_{1}^{2}{(\dfrac{y^3}{4}+y^{-3})dy}$

$L=(\dfrac{y^{3+1}}{4\times4}+\dfrac{y^{-3+1}}{-3+1})_{1}^{2}$

$L=(\dfrac{y^4}{16}+\dfrac{y^{-2}}{-2})_{1}^{2}$

Put the limits

$L=(\dfrac{2^4}{16}+\dfrac{2^{-2}}{-2}-\dfrac{1^4}{16}-\dfrac{(1)^{-2}}{-2})$

$L=\dfrac{21}{16}$

Hence, The arc length is $\dfrac{21}{16}$

6 0

2 years ago

The label on a bag of chocolates states that there are 0.384 pounds of chocolates.

charle [14.2K]

Answer:

Answer:The chocolate are 0.0042 lighter than the stated on the label

4 0

2 years ago

An EPA contractor needs to test the concentration of a substance in ten samples of the ground water. Seventy samples were

olga55 [171]

Answer:

Systematic sampling

Step-by-step explanation:

An EPA contractor needing to test the concentration of a substance in ten samples out seventy samples provided form a single source at regular time intervals.

For the contractor to effectively carry out the testing he has to employ a Non-probability system of sampling which is called Systematic sampling, because in systematic sampling we can assume the population size (x ) which in this case is 70 and the sample size( n ) to be 10

He will have to select ; ( x / n )^th of the sampling frame for best results

7 0

3 years ago