Answer:
x = ±i(√6 / 2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
<u>Algebra II</u>
Imaginary root i
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
2x² + 3 = 0
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Subtraction Property of Equality] Subtract 3 on both sides: 2x² = -3
- [Division Property of Equality] Divide 2 on both sides: x² = -3/2
- [Equality Property] Square root both sides: x = ±√(-3/2)
- Simplify: x = ±i(√6 / 2)
Answer:
x ≈ ±20.086/√(t - 1)
Step-by-step explanation:
ln(t - 1) + ln(x²) = 6
Recall that lnu + lnv = ln(uv). Then
ln(t - 1) + ln(x²) = ln[(t-1)x²] = 6
Take the natural antilogarithm of each side
(t - 1)x² = e⁶
Divide each side by t - 1
x² = e⁶/(t-1)
Take the square root of each side
x = ±e³/√(t - 1)
x ≈ ±20.086/√(t - 1)
1 person make 3 cakes.
40 people make 40 x 3 = 120 cakes.
15% were chocolate = 15% x 120 = 0.15 x 120 = 18
Answer: There were 18 chocolate cakes made for bake sale.