<h3>1.</h3>
The picture shows 5 groups of 3 bars. Each bar represents 1/10. We take the picture to mean that ...
... (15/10) / 5 = 3/10
In decimal:
... 1.5 / 5 = 0.3
<h3>2.</h3>
The picture shows 3 groups of 2 bars. Each bar represents 1/10. We take the picture to mean that ...
... (6/10) / 3 = 2/10
In decimal:
... 0.6 / 3 = 0.2
<h3>3.</h3>
The picture shows 4 groups, each consisting of 1 large square, 1 bar, and 4 small squares. We take the picture to mean that ...
... (4 + 4/10 + 16/100) / 4 = 1 + 1/10 + 4/100
In decimal:
... 4.56 / 4 = 1.14
Please note that 16/100 is equivalent to 1/10 + 6/100. In order to do the division, one of the 1/10 bars needed to be changed into 10 small squares, 10/100.
<h3>4.</h3>
The picture shows 3 groups, each consisting of 1 large square, 3 bars, and 2 small squares. We take the picture to mean that ...
... (3 + 9/10 +6/100) / 3 = 1 +3/10 + 2/100
In decimal:
... 3.96 / 3 = 1.32
Answer:
y=-1/2x-3
I hope this helps u :)
Step-by-step explanation:
Answer:
Integers include both positive and negative numbers, and there are several rules for adding integers. Adding two positive integers together will always result in a positive integer. For example, 6 + 4 = 10. To add two negative integers, add the numbers together and place a negative sign in front of the answer.
1. Start with ΔCIJ.
- ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
- the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
- ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.
2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So
m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.
3. Consider ΔCKL.
- ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
- ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
- the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
- ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.
4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So
m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.
5. ΔABC is isosceles, then angles adjacent to the base are congruent:
m∠KBA=m∠JAB → 222°-8x=205°-7x,
7x-8x=205°-222°,
-x=-17°,
x=17°.
Then m∠CAB=m∠CBA=205°-7x=86°.
Answer: 86°.
Number 2 is 6
i dont know number 3
<span> number 4 is _x-intercept = -12/11 = -1.09091 y-intercept = -12/4 = -3
</span>number 5 is x=12 ,<span>y=<span>−8</span></span><span>y=<span>-<span>8</span></span></span>
