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harkovskaia [24]
3 years ago
14

Which is the standard form of the equation of the parabola that has a vertex of (3, 1) and a directric of x = -2?

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
8 0
Check the picture below.  So,the parabola looks like so, notice the distance "p". since the parabola is opening to the right, then "p" is positive, thus is 5.

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
\boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}})} \\\\
(x-{{ h}})^2=4{{ p}}(y-{{ k}}) \\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\

\bf -------------------------------\\\\
\begin{cases}
h=3\\
k=1\\
p=5
\end{cases}\implies (y-1)^2=4(5)(x-3)\implies (y-1)^2=20(x-3)
\\\\\\
\cfrac{1}{20}(y-1)^2=x-3\implies \boxed{\cfrac{1}{20}(y-1)^2+3=x}

fgiga [73]3 years ago
3 0

Answer:

20(x-3) = (y-1)^2

Step-by-step explanation:

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6. Andy scored 90 on the last history exam. He scored 81 this time. By what percent did his score decrease?​
allsm [11]

Answer:

His score decreased by 9 percent this time.

Step-by-step explanation:

From his first history exam he had a score of 90 percent. The difference between his first score and present score is given by

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6 0
1 year ago
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Marysya12 [62]

Answer:

D) It is doubled

Step-by-step explanation:

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8 0
3 years ago
Simplify\:\frac{\sqrt{5}}{\sqrt{3}}
avanturin [10]

\dfrac{\sqrt 5}{\sqrt 3} =\sqrt{\dfrac 53} \approx 1.291

7 0
3 years ago
Need help on this one
malfutka [58]

Answer:

3

Step-by-step explanation:

To simplify this expression, we will simply work with the numerator, then the denominator, and then the fraction as a whole, following PEMDAS.

Numerator:  12 - 6 + 5 * (-3)^2

= 12 - 6 + 5 * (9)

= 12 - 6 + 45

= 6 + 45

= 51

Denominator:  17

So our simplified fraction is as follows:

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Cheers.

3 0
3 years ago
What is the first step in solving 3=r/10
True [87]

Answer:

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Step-by-step explanation:

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