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4 years ago

CAN YOU PLEASE HELP! ASAP! PLS &TY!

Chemistry

2 answers:

dybincka [34]4 years ago

3 0

Answer:

Hey I really hope this helps!

Explanation:

Temperatures do not affect radioactivity at all. This has been tested many times and at extreme temperatures. Temperature is the average vibrational kinetic energy of the molecules of some object. ... Radioactive decay is caused by imbalances in the nuclear and electroweak forces inside the nucleus of an atom.

Brainliest??? Have a good day!!

alex41 [277]4 years ago

3 0

Answer:

Temperature does not affect the rate of radioactive decay as it is a spontaneous process unaffected by physical conditions.

hope this helps :)

I'd appreciate if you'd mark me brainliest because ive

been stuck on the same rank for wayyy too long :(

Goodluck! :)

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How can I calculate the mass percent of carbon, nitrogen and oxygen in caffeine, C8H10N4O2.

Ahat [919]

You must first calculate the total weight of 1 mole of the substance. You do this by finding the molar weights on the periodic table of each of the elements in the compound:

$8(12.01g)+10(1.008g)+4(14.007g)+2(15.999g)=96.08g+10.08g+56.028g+31.998g=194.186g$

So now we take the amount of each element that is given in the compound and divide it by the total mass of the compound:

Carbon: 96.08g

$\frac{96.08g}{194.186g}= 0.49478=49.48$

Carbon = 49.48%

Nitrogen: 56.028g

$\frac{56.028g}{194.186g}=0.28853=28.85$

Nitrogen = 28.85%

Oxygen: 31.998g

$\frac{31.998g}{194.186g} =0.16478=16.48$

Oxygen = 16.48%

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3 years ago

What volume of solution would be present if 40.0 g Caci, would be used to make a 0.600M

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Answer:

$\large \boxed{\text{601 mL}}$

Explanation:

1. Calculate the moles of CaCl₂.

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Step 2. Calculate the volume of CaCl₂ solution

$\begin{array}{rcl} n &= &\dfrac{c}{V}\\\\\dfrac{\text{0.600 mol}}{\text{1 L}} &=& \dfrac{\text{0.3604 mol}}{V}\\\\ \dfrac{0.600V}{\text{1 L}} & = & 0.3604\\\\0.600V &= & \text{0.3604 L}\\V & = & \dfrac{\text{0.3604 L}}{\text{0.600 L}}\\\\ & = & \text{0.601 L}\\& = & \textbf{601 mL}\\\end{array}\\\text{The volume of the solution would be $\large \boxed{\textbf{601 mL}}$}$

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