These values may represent the amount of pulling force that we exert on each other or in other words exert forces on both parties.
The answer may differ as well but keep in mind the values should be equal.
Note:
The answer is not about helping each other or the "spring balance". We are not talking about the literal moral values instead we are talking about Chemistry and Science.
The total quantity of heat evolved in converting the steam to ice is determined as -12,928.68 J.
<h3>
Heat evolved in converting the steam to ice</h3>
The total heat evolved is calculated as follows;
Q(tot) = Q1(steam to boiling point) + Q2(boiling point to ice) +Q3(freezing to -42 ⁰C)
where;
Q = = mcΔθ
where;
- m is mass, (mass of water = 18 g/mol)
- c is specific heat capacity,
- Δθ is change in temperature
Q(tot) = 2(18)(2.01)(100 - 135) + 2(18)(2.01)(0 - 100) + 2(18)(2.09)(-42 - 0)
Q(tot) = -12,928.68 J
Thus, the total quantity of heat evolved in converting the steam to ice is determined as -12,928.68 J.
Learn more about heat here: brainly.com/question/13439286
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Symbiosis describes close<span> interactions between two or more different species. There are four main types of symbiotic relationships: mutualism, commensalism, parasitism and competition.</span>
Answer:
378mL
Explanation:
The following data were obtained from the question:
Pressure (P) = 99.19 kPa
Temperature (T) = 28°C
Number of mole (n) = 0.015 mole
Volume (V) =...?
Next, we shall convert the pressure and temperature to appropriate units. This is illustrated below:
For Pressure:
101.325 KPa = 1 atm
Therefore, 99.19 kPa = 99.19/101.325 = 0.98 atm
For Temperature:
T(K) = T(°C) + 273
T(°C) = 28°C
T(K) = 28°C + 273 = 301K.
Next we shall determine the volume of N2. The volume of N2 can be obtained by using the ideal gas equation as shown below:
PV = nRT
Pressure (P) = 0.98 atm
Temperature (T) = 301K
Number of mole (n) = 0.015 mole
Gas constant (R) = 0.0821atm.L/Kmol.
Volume (V) =...?
0.98 x V = 0.015 x 0.0821 x 301
Divide both side by 0.98
V = (0.015 x 0.0821 x 301) /0.98
V = 0.378 L
Finally, we shall convert 0.378 L to millilitres (mL). This is illustrated below:
1L = 1000mL
Therefore, 0.378L = 0.378 x 1000 = 378mL
Therefore, the volume of N2 collected is 378mL
