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Rudik [331]
3 years ago
7

Draw the Lewis dot structure for RbIO2. Include all hydrogen atoms and nonbonding electrons. Show the formal charges of all atom

s. To change the symbol of an atom, double-click on the atom and enter the letter of the new atom.

Chemistry
1 answer:
Rzqust [24]3 years ago
7 0

Answer : The Lewis-dot structure of RbIO_2  is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, RbIO_2

As we know that rubidium has '1' valence electrons, iodine has '7' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in RbIO_2 = 1 + 7 + 2(6) = 20

As we know that RbIO_2  is an ionic compound because it is formed by the transfer of electron takes place from metal to non-metal element.

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A solution of K2SO4 and KCl is added to a solution of Ba(NO3)2. BaS0₄ (s) will precipitate out of this combined solution.

Molecular equation

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This equation represents a double displacement (replacement) reaction, also called a metathesis reaction, in which the reactant ions exchange places to form new products. The general equation is:

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Complete ionic equation: Includes all ions and the precipitate.

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