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Rudik [331]
3 years ago
7

Draw the Lewis dot structure for RbIO2. Include all hydrogen atoms and nonbonding electrons. Show the formal charges of all atom

s. To change the symbol of an atom, double-click on the atom and enter the letter of the new atom.

Chemistry
1 answer:
Rzqust [24]3 years ago
7 0

Answer : The Lewis-dot structure of RbIO_2  is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, RbIO_2

As we know that rubidium has '1' valence electrons, iodine has '7' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in RbIO_2 = 1 + 7 + 2(6) = 20

As we know that RbIO_2  is an ionic compound because it is formed by the transfer of electron takes place from metal to non-metal element.

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If the average atomic mass of hydrogen in nature is 1.0079, what does that tell you about the percent composition of H-1 and H-2
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Answer:

That the isotope H-1 is the most abundant in nature.

Explanation:

Hello!

In this case, since the average atomic mass of an element is computed considering the mass of each isotope and the percent abundance each, for hydrogen we would set up something like this:

m_H=m_{H_1}*\%abund_{H_1}+m_{H_2}*\%abund_{H_2}

Moreover, since the isotope notation H-1 and H-2 means that the atomic mass of H-1 is 1 amu, that of H-2 is 2 amu and the average one is 1.0079 amu, we can infer that the most of the hydrogen in nature is H-1 as the most of it composes the average hydrogen atom.

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4 0
3 years ago
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jolli1 [7]

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1.02 moles of AlCl3

Explanation:

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