All categories

3 years ago

The points A(12,7), B(12,-3), C(-2,-3), and D(-2,7) form rectangle ABCD. Which point is halfway between A and B?

2 answers:

katrin2010 [14]3 years ago

7 0

To find the answer, you must find the midpoint of their x-coordinates and their y-coordinates. To do that, you take the average between their x and y-coordinates.
So, in this case, it is:
x: (12+12)/2 = 24/2 = 12
y: (7-3)/2 = 4/2 = 2

So, the answer is: (12,2)

Tom [10]3 years ago

3 0

The X axis will remain the same. Then you find the distance between the y values which is 10. Since you're finding the halfway point you have to divide your distance by two, by which you'll get 5. Then you can either add 5 to -3 or subtract 5 from 7. This will give you the coordinate points (12,2).

You might be interested in

1. for what constant k must f(k) always equal the constant term of f(x) for any polynomial f(x) 2. If we multiply a polynomial b

DIA [1.3K]

Answer:

1. k=0

2. yes, result is still a polynomial.

3. yes, f and g must have the same degree to have deg(f+g) < deg(f) or deg(g)

Step-by-step explanation:

1. for what constant k must f(k) always equal the constant term of f(x) for any polynomial f(x)

for k=0 any polynomial f(x) will reduce f(k) to the constant term.

2. If we multiply a polynomial by a constant, is the result a polynomial?

Yes, If we multiply a polynomial by a constant, the result is always a polynomial.

3. if deg(f+g) is less than both deg f and deg g, then must f and g have the same degree?

Yes.

deg(f+g) < deg(f) and

deg(f+g) < deg(g)

then it means that the two leading terms cancel out, which can happen only if f and g have the same degree.

5 0

4 years ago

Find the proper answer

Temka [501]

I think the answer is C

8 0

3 years ago

Write a polynomial in standard form that meets the following conditions. Assume a=1 and your function is f(x), The zeros are 5 a

jeka57 [31]

Polynomials are equations that uses variables and several terms

The polynomial in standard form is f(x) = x^2 - x -20

<h3>How to determine the polynomial</h3>

The polynomial has 2 zeros.

So, the form of the polynomial is:

f(x) = a(x - x1)(x - x2)

The zeros of the polynomial are 5 and -4.

So, the equation becomes

f(x) = a(x - 5)(x + 4)

The value of a = 1.

So, we have;

f(x) = 1(x - 5)(x + 4)

This gives

f(x) = (x - 5)(x + 4)

Expand

f(x) = x^2 - x -20

Hence, the polynomial in standard form is f(x) = x^2 - x -20