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4 years ago

14

What number would complete the pattern below? 107 98 90 83 77 __ 68 65

2 answers:

Tanzania [10]4 years ago

7 0

72 would be the correct answer

Hatshy [7]4 years ago

3 0

Start at 107...
107 (-9) = 98
98 (- 8) = 90
90 (-7) = 83
83 (-6) = 77
77 (-5) = 72
72 (-4) = 68
68 (-3) = 65

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2 times the sum of a number and 4 is no more than three times the sum of a number and 7 decreased by 4

anygoal [31]

$2(x+4) \geq 3((x+7)-4) \\ 2x+8 \geq 3(x+7)-12 \\ 2x+8 \geq 3x+21-12 \\ 2x+8 \geq 3x+9 \\ 2x \geq 3x+1 \\ -x \geq 1 \\ x \leq -1$

5 0

3 years ago

The pentagon below has an area of 8.3 square centimeters and a side of 2.2. What is the approximate length of the apothem? A.0.4

nalin [4]

Answer:

C. 1.5 cm

Step-by-step explanation:

A pentagon is a polygon with 5 sides.

The formula for the area of a regular polygon is

$A=\frac{1}{2}ap$

where a is the apothem and p is the perimeter. The perimeter is found by multiplying the number of sides of the figure by the length of 1 of those sides:

5(2.2) = 11

Now we have everything we need to solve for the length of the apothem.

$8.3=\frac{1}{2}a(11)$

Begin by multiplying both sides by 2 to get rid of the fraction, so

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a = 1.5090909 or

C. 1.5 cm

3 0

3 years ago

Read 2 more answers

A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a

kkurt [141]

Answer:

$b=h=\sqrt{6}$ m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box= $2b^2+4bh$

$2b^2+4bh=36$

$b^2+2bh=18$

$2bh=18-b^2$

$h=\frac{18-b^2}{2b}$

Volume of box, V= $b^2h$

Substitute the values

$V=b^2\times \frac{18-b^2}{2b}$

$V=\frac{1}{2}(18b-b^3)$

Differentiate w. r.t b

$\frac{dV}{db}=\frac{1}{2}(18-3b^2)$

$\frac{dV}{db}=0$

$\frac{1}{2}(18-3b^2)=0$

$\implies 18-3b^2=0$

$\implies 3b^2=18$

$b^2=6$

$b=\pm \sqrt{6}$

$b=\sqrt{6}$

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

$\frac{d^2V}{db^2}=-3b$

At $b=\sqrt{6}$

$\frac{d^2V}{db^2}=-3\sqrt{6}$

Hence, the volume of box is maximum at $b=\sqrt{6}$ .

$h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}$

$h=\frac{18-6}{2\sqrt{6}}$

$h=\frac{12}{2\sqrt{6}}$

$h=\sqrt{6}$

$b=h=\sqrt{6}$ m

7 0

3 years ago

A student skipped a step swhen she tried to convert 15 hours to seconds and she got the following in correct resort

Tomtit [17]

15*6=90 so 15* 60=900

4 0

4 years ago

What is the answer for the equation above

Dimas [21]

Add 5+3 raised to the 2nd which givea u (8)^2
do the 5 squared which gives u 1+25-23

evaluate 8^2=64
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3 0

3 years ago