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3 years ago

Can you please help I'm stuck on this problem and I keep on getting it wrong

Mathematics

2 answers:

Lorico [155]3 years ago

7 0

Check the picture below.

lidiya [134]3 years ago

6 0

Answer:

68°

Step-by-step explanation:

Since WX and ZY are parallel, angle W and angle Z should add up to 180°

W + Z = 180°

112° + Z = 180°

Z = 68°

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The perimeter of an equilateral triangle is 4.8 cm. Which equation gives the length of one side?

iVinArrow [24]

Answer:

14.4

Step-by-step explanation:

7 0

3 years ago

Suppose that triangle ABC is a right triangle with a right angle at C and hypotenuse C. Also note that a is the length of the si

gavmur [86]

Answer:

The value of a is 7.4833. The value of $A=29.9262^0$ and $B=60.0735^0$ .

Step-by-step explanation:

Consider the provided information.

The required figure is shown below:

We need to find the value of a.

Calculate the value of a by using Pythagorean theorem.

$a^2+b^2=c^2$

$a^2+(13)^2=(15)^2$

$a^2=225-169$

$a^2=56$

$a=7.4833$

Hence, the value of a is 7.4833.

Now find the value of angle A as shown:

$\sin A=\frac{a}{c}$

$\sin A=\frac{7.4833}{15}$

$A=sin^{-1}(0.4989)$

$A=29.9262^0$

Find the value of angle B as shown:

$\sin B=\frac{b}{c}$

$\sin B=\frac{13}{15}$

$B=sin^{-1}(0.8667)$

$B=60.0735^0$

Hence, the value of $A=29.9262^0$ and $B=60.0735^0$ .

6 0

3 years ago

Multiply<br><br> 3 sqrt (2) X 2 sqrt (8) X sqrt (3) X sqrt (6)

erma4kov [3.2K]

That is 6 * sqrt(2*8*3*6)

= 6 sqrt 16 * sqrt 18

= 6 *4 * sqrt 9 * sqrt2

= 6*4*3 sqrt2

= 72 sqrt 2

7 0

4 years ago

The probability that an Oxnard University student is carrying a backpack is .70. If 10 students are observed at random, what is

Rus_ich [418]

Answer:

35.03% probability that fewer than 7 will be carrying backpacks

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they are carrying a backpack, or they are not. The probability of a student carrying a backpack is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that an Oxnard University student is carrying a backpack is .70.

This means that $p = 0.7$

If 10 students are observed at random, what is the probability that fewer than 7 will be carrying backpacks

This is $P(X < 7)$ when $n = 10$ . So

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.7)^{0}.(0.3)^{10} = 0.000006$

$P(X = 1) = C_{10,1}.(0.7)^{1}.(0.3)^{9} = 0.0001$

$P(X = 2) = C_{10,2}.(0.7)^{2}.(0.3)^{8} = 0.0014$

$P(X = 3) = C_{10,3}.(0.7)^{3}.(0.3)^{7} = 0.0090$

$P(X = 4) = C_{10,4}.(0.7)^{4}.(0.3)^{6} = 0.0368$

$P(X = 5) = C_{10,5}.(0.7)^{5}.(0.3)^{5} = 0.1029$

$P(X = 6) = C_{10,6}.(0.7)^{6}.(0.3)^{4} = 0.2001$

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.000006 + 0.0001 + 0.0014 + 0.0090 + 0.0368 + 0.1029 + 0.2001 = 0.3503$

35.03% probability that fewer than 7 will be carrying backpacks

4 0

4 years ago

matthews pet dog is 7% heavier than Harrison's pet dog , and Janice's pet dog is 20% lighter than Harrisons, by what percent is

statuscvo [17]

27% hope this helps good luck

7 0

3 years ago