All categories

3 years ago

⚠️⚠️⚠️GIVING AWAY HUGE POINTS FOR ANYONE WHO COMPLETES THIS AND GETS THEM RIGHT!!!!!!!⚠️⚠️⚠️

Mathematics

1 answer:

Firlakuza [10]3 years ago

5 0

1st picture

The average speed for his journey from York to Blackpool is 61.4 KM/H

You might be interested in

Given the function defined below, what is the value of the 4th term?

MakcuM [25]

Answer:

The 4 t h term is f(4) = 143

Step-by-step explanation:

Explanation:-

Given function f(1) = -4

Given 'nth' term is f(n) = -3f(n-1) +5

Put n =2 f(2) = -3 f(2-1) +5

= -3 f(1) +5

= -3 (-4) +5

= 12 +5

f(2) = 17

put n= 3

f(n) = -3f(n-1) +5

f(3) = -3 f(3-1) +5

= -3f(2) +5

= -3(17) +5

= -51+5

f(3) = -46

Put n=4

f(n) = -3f(n-1) +5

f(4) = -3f(4-1) +5

f(4) = -3f(3)+5

f(4) = -3(-46)+5

f(4) = 138 +5

f(4) = 143

Final answer:-

The 4 t h term is f(4) = 143

6 0

2 years ago

terry,sasha and harry each chose a number. terry's number is ten times as much as sasha's. harry's number is 1 over 10 of sasha'

PilotLPTM [1.2K]

Harry's number is 0.04, and Terry's number is 4.

Hope this helps!

8 0

2 years ago

What is the value of 4 (3) - 17

yawa3891 [41]

Answer:

4 times 3 is 12 and 12-17 is -5.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Will mark brainlist if right

dlinn [17]

Answer: C.

Step-by-step explanation:

7 0

1 year ago

The pressure applied to a leverage bar varies inversely as the distance from the object. If 150 pounds is required for a distanc

AlexFokin [52]

Answer:

500 pounds

Step-by-step explanation:

Let the pressure applied to the leverage bar be represented by p

Let the distance from the object be represented by d.

The pressure applied to a leverage bar varies inversely as the distance from the object.

Written mathematically, we have:

$p \propto \dfrac{1}{d}$

Introducing the constant of proportionality

$p = \dfrac{k}{d}$

If 150 pounds is required for a distance of 10 inches from the object

p=150 pounds
d=10 inches

$150 = \dfrac{k}{10}\\\\k=1500$

Therefore, the relationship between p and d is:

$p = \dfrac{1500}{d}$

When d=3 Inches

$p = \dfrac{1500}{3}\\\implies p=500$ pounds$

The pressure applied when the distance is 3 inches is 500 pounds.

4 0

3 years ago