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miss Akunina [59]
3 years ago
9

A rectangle is 11 inches long and 8 inches wide find its area

Mathematics
2 answers:
sineoko [7]3 years ago
7 0

Answer:

the area of the rectangle is 88

Step-by-step explanation:

pls mark brainliest

tatyana61 [14]3 years ago
5 0

Answer: 88 in.

To find the area of a square or rectangle, times the width by the length:

11 in. x 8 in. = 88 in.

Hope this helped you out a bit! :D

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Help anyone can help me do this question,I will mark brainlest.​
andrey2020 [161]

Answer:

8 cm

Step-by-step explanation:

  1. AM = MC = BM = (1/2) BC => AM , MC , BM = 5, => BC = 10
  2. apply pytago => (AC ^ 2) + (AB ^ 2) = (BC ^2)
  3. AB = \sqrt{BC ^2  - AC ^2} = \sqrt{10 ^2 -  6 ^ 2} = 8 (cm)
5 0
3 years ago
Read 2 more answers
Based on the drawing, Which can be used to prove PQR ≅ STV?
natta225 [31]

Answer:

Option (2) is correct.

Based on the drawing, SAS can be used to prove PQR ≅ STV

Step-by-step explanation:

We have to find the criterion by which the two given triangle can be prove similar from the given options.

Consider, the given triangles from the drawing given

ΔPQR and ΔSTV,

PR = VS  (Given)

∠QRP = ∠TVS ( Given)

and, QR = TV (given)

Thus,  PQR ≅ STV  ( SAS CRITERION)

For SAS criterion , we need to show that two sides and the angle between those sides are equal .

Thus, option (2) is correct.


5 0
3 years ago
WHAT IS (2x2A5)x35= please answer
Anna71 [15]
The answer is 140x^5
4 0
3 years ago
Simplify. Rewrite the expression in the form b^n. b^10/b^6
Vlad1618 [11]

Answer:

<h2>The answer is b⁴</h2>

Step-by-step explanation:

\frac{ {b}^{10} }{ {b}^{6} }

Using the rules of indices

That's

\frac{ {a}^{x} }{ {a}^{y} }  =  {a}^{x - y}

Since the bases are the same and are dividing we subtract the exponents

So we have

\frac{ {b}^{10} }{ {b}^{6} }  =  {b}^{10 - 6}

We have the final answer as

<h2>b⁴</h2>

Hope this helps you

6 0
3 years ago
Read 2 more answers
Pleaseeeee help <br> ASAP
melisa1 [442]

Answer:

6.6

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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