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3 years ago

If Y is inversely proportional to x and y=4 when x= 100, what is the value of y when x=250

Mathematics

1 answer:

hichkok12 [17]3 years ago

7 0

Answer:

y=10

Step-by-step explanation:

$\frac{4}{100}$ = $\frac{y}{250}$

cross-multiply, 4*250=100y

isolate the variable and solve for y, 1000=100y

divide 100 on both sides, 10=y

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Perry divided up some candy to give equally to his six friends if c represents the total amount write an expression to represent

Delicious77 [7]

Use easy numbers if you get confused on problems like these.

I'm going to use 12 instead of c.
Since you have 12 pieces of candy and 6 friends, each friend would get 2 pieces, because 12/6=2.

Now, substitute c for 12, and you get c/6.

Hope this helps!

7 0

3 years ago

Read 2 more answers

Daniel wants to buy cookies for her friends. The area of a cookie is 113.04 in2. What is the circumference of the cookie?

prisoha [69]

Answer:

The circumference of the cookie is 37.68 inches.

Step-by-step explanation:

We have,

The area of a cookie is 113.04 square inches.

It is circular in shape. The area of circle is given by :

$A=\pi r^2$

r is radius of circle

$r=\sqrt{\dfrac{A}{\pi}} \\\\r=\sqrt{\dfrac{113.04}{3.14}} \\\\r=6\ \text{inch}$

The circumference of circular shaped object is given by :

$C=2\pi r\\\\C=2\times 3.14\times 6\\\\C=37.68\ \text{inch}$

So, the circumference of the cookie is 37.68 inches.

7 0

3 years ago

In the manufacturing division of a particular company, there are 68 hourly employees and 30 for salaried employees to employees

umka21 [38]

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3 years ago

Which of these figures represents a line?

Anastaziya [24]

Answer:

Figure C

Step-by-step explanation:

Figure A represents a ray because it has arrow only on one end.

Figure B is a line segment because it stops on both ends.

Figure C is a line because it has arrow on both ends.

Figure D is an angle, because it is 2 rays joined at a vertex.

6 0

3 years ago

I have the first part but I don't know how to do the second part<br><br> h e l p

Debora [2.8K]

$\bf \begin{array}{cll} \stackrel{ordinal}{position}&\stackrel{term}{value}\\ \cline{1-2} 1&12\\ 2&12+d\\ 3&12+d+d\\ 4&12+d+d+d\\ &12+3d \end{array}\qquad \implies ~\hfill \begin{array}{llll} \stackrel{\textit{4th term}}{12+3d}~~=~~\stackrel{\textit{4th value}}{3}\\\\ 3d=-9\implies d = \cfrac{-9}{3}\\\\ \stackrel{\textit{common difference}}{d = -3} \end{array}$

well, we know the common difference is -3, to go from the 4th term to the 8th term, we need to add "d" 4 times or namely 3+4(-3), likewise to go from the 13th term to the 19th term we have to add "d" 6 times, or namely -24 + 6(-3).

$\bf \stackrel{\textit{8th term}}{3+4(-3)}\implies 3-12\implies -9 \\\\\\ \stackrel{\textit{19th term}}{-24 + 6(-3)}\implies -24-18\implies -42$

3 0

3 years ago