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34kurt
3 years ago
5

Rob peeled 125 oranges in 5 hours. At that rate, how many oranges would he peel in 12 minutes?

Mathematics
2 answers:
marin [14]3 years ago
6 0

Answer:

\boxed {\tt 5 \ oranges}

Step-by-step explanation:

Let's set up a proportion.

\frac{oranges}{minutes} =\frac{oranges}{minutes}

He can peel 125 oranges in 5 hours. First, let's find the minutes in 5 hours.

There are 60 minutes in 1 hour, so multiply 60 and 5 (60*5=300). There are 300 minutes in 5 hours.

\frac{125 \ oranges}{300 \ minutes}=\frac{oranges}{minutes}

We don't know how many oranges he can peel in 12 minutes. So we say he can peel x oranges in 12 minutes.

\frac{125 \ oranges}{300 \ minutes}=\frac{x \ oranges}{12 \ minutes}

\frac{125 \ }{300 \ }=\frac{x \ }{12 }

Solve for x by isolating it. x is being divided by 12. The inverse of division is multiplication. Multiply both sides of the proportion by 12.

12*\frac{125 \ }{300 \ }=\frac{x \ }{12 \ }*12

12*\frac{125 \ }{300 \ }=x

12*0.416666667=x

5=x

Rob can peel 5 oranges in 12 minutes.

vlabodo [156]3 years ago
6 0

Answer:

5 oranges in 12 minutes

Step-by-step explanation:

125  \div 5 = 25

25  \div 60  = 0.41

0.41 \times 12 = 5

what i did here was I took the original amount (125), divided it by 5 which is 25 oranges per hour

1 hr = 60 mins

then I divided 25 oranges by 60 mins, then times it by 12 to get 5 around 5 oranges in 12 minutes.

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Answer:

1716 ;

700 ;

1715 ;

658 ;

1254 ;

792

Step-by-step explanation:

Given that :

Number of members (n) = 13

a. How many ways can a group of seven be chosen to work on a project?

13C7:

Recall :

nCr = n! ÷ (n-r)! r!

13C7 = 13! ÷ (13 - 7)!7!

= 13! ÷ 6! 7!

(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)

1235520 / 720

= 1716

b. Suppose seven team members are women and six are men.

Men = 6 ; women = 7

(i) How many groups of seven can be chosen that contain four women and three men?

(7C4) * (6C3)

Using calculator :

7C4 = 35

6C3 = 20

(35 * 20) = 700

(ii) How many groups of seven can be chosen that contain at least one man?

13C7 - 7C7

7C7 = only women

13C7 = 1716

7C7 = 1

1716 - 1 = 1715

(iii) How many groups of seven can be chosen that contain at most three women?

(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)

Using calculator :

(15 * 35) + (6 * 21) + (1 * 7)

525 + 126 + 7

= 658

c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?

(First in second out) + (second in first out) + (both out)

13 - 2 = 11

11C6 + 11C6 + 11C7

Using calculator :

462 + 462 + 330

= 1254

d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?

Number of ways with both in the group = 11C5

Number of ways with both out of the group = 11C7

11C5 + 11C7

462 + 330

= 792

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