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aliina [53]
3 years ago
11

The surface area of a cone is found using the formula SA = Pir2 + Pirl. Describe what each part of the formula represents and ho

w these parts are used to calculate the surface area.

Mathematics
2 answers:
N76 [4]3 years ago
6 0

Answer:

<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will help uh</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

Bess [88]3 years ago
5 0

Answer:  the first part is the area of the base:  πr²

You take the radius given, (or half of the diameter given) square that and multiply by the value of Pi, commonly 3.14 or 3.1416  

The second part is the area of the lateral surface. πrh That is the radius times π times the height of the cone.

Step-by-step explanation:

The formula as shown is confusing to me. It is better to show exponents with superscript if possible, or use the caret ^ [shift + 6] on a keyboard before the 2.

The second part is the area of the lateral surface. πrh That is the radius times π times the height of the cone. (using h instead of l seems less confusing as lower case L looks like 1 in some fonts) But people do use<em> πrl  </em>I realize.

Add the two surface areas together to get the total surface area of the cone.

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4 over three means 4 pieces out of 3. 4 pieces divided by 2 is 2 pieces.

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Multiply all of the numbers together: 5 x 2 x 8 = 10 x 8 = 80 ways

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2 years ago
The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4. Suppose 64 golfers play
Vilka [71]

Answer:

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 75, \sigma = 4, n = 64, s = \frac{4}{\sqrt{64}} = 0.5

Find the probability that the average score of the 64 golfers exceeded 76.

This is 1 subtracted by the pvalue of Z when X = 64.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{76 - 75}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

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3 years ago
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