Answer:
The maximum height is:
The ball reaches the ground in 1.79 s.
Step-by-step explanation:
We need to take the derivative and equal to zero to find the time at the maximum height.
(1)
Now, we just need to put t(max) into equation (1) to find h(max)
If we want to get the time when the ball reaches the ground we just need to equal h(t) to zero.
Let's solve this quadratic equation.
We will get two solutions and we must choose the positive value.
t1 = 1.79 u
t2 = -0.10 u
Therefore, the ball reaches the ground in 1.79 u.
I hope it helps you!
Answer:
8x³ + 12x² - 16x - 16
General Formulas and Concepts:
- Order of Operations: BPEMDAS
- Distributive Property
Step-by-step explanation:
<u>Step 1: Define expression</u>
(4x² - 2x - 4)(2x + 4)
<u>Step 2: Simplify</u>
- Expand: 8x³ - 4x² - 8x + 16x² - 8x - 16
- Combine like terms (x²): 8x³ + 12x² - 8x - 8x - 16
- Combine like terms (x): 8x³ + 12x² - 16x - 16
Answer:
mean
Step-by-step explanation: