All categories

2 years ago

Please help with this :(

Mathematics

2 answers:

kirill [66]2 years ago

8 0

Answer: -m^4

Step-by-step explanation:

pentagon [3]2 years ago

3 0

Answer:

-1

Step-by-step explanation:

-1 x -1 x -1 = 1

You might be interested in

Find the slope of the line that passes through (10,8) and (8,0).

N76 [4]

Answer:

The slope of the line that passes through points ( -10, -8 ) and ( -8, -16 ) is -4.

Explanation:

Points given = ( -10, -8) and ( -8, -16)

Slope = ?

( -10, -8 ) : x1 = -10 and y1 = -8

( -8, -16 ) : x2 = -8 and y2 = -16

We know,

slope = y2 - y1 / x2 - x1

Slope = -16 - ( -8) / -8 - (-10)

slope = -16 + 8 / -8 + 10

slope = -8 / 2

slope = -4

Therefore, slope of the line that passes through points ( -10, -8 ) and ( -8, -16 ) is -4.

Step-by-step explanation:

3 0

2 years ago

How to solve 4p^2-48p+128

xxTIMURxx [149]

Step-by-step explanation:

4p^2 - 48p + 128

use calculator

7 0

2 years ago

The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probabilit

Alik [6]

Answer:

a) The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b) We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean $\mu$ , standard deviation $\sigma$

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b. If the length of pregnancy is in the lowest a%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

8 0

2 years ago

What is x\3 so solve for x if it equals 90

Nataliya [291]

X= 270
simplify the equation using cross multiplication

8 0

3 years ago

Read 2 more answers

Point A is at (-1,-9) and Point M is at (0.5,-2.5).

leva [86]

Midpoint Formula: $(\frac{x_2+x_1}{2},\frac{y_2+y_1}{2})$

So firstly, let's start with the x-coordinates. Since we know the midpoint's x-coordinate and point A's x-coordinate, we can solve for point B's x-coordinate as such:

$\frac{-1+x}{2}=0.5\\\\-1+x=1\\\\x=2$

Next, do the same thing except solve for the y-coordinate and using point A's y-coordinate and the midpoint's y-coordinate:

$\frac{-9+y}{2}=-2.5\\\\-9+y=-5\\\\y=4$

<u>Putting it together, point B's coordinates are (2,4).</u>

4 0

2 years ago