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Setler79 [48]
2 years ago
12

What is the surface area of a right circular cylinder with a diameter of 14 meters and a height of 9 meters

Mathematics
1 answer:
Umnica [9.8K]2 years ago
4 0

Answer:

This is your answer ☺️☺️☺️

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Will the following list have a large or small Standard Deviation?
jek_recluse [69]

Answer:

large

Step-by-step explanation:

3 0
2 years ago
Given circle P with arc AE=53, arc BA=68 and arc CB=72 match the following angles with their corresponding measurements
11Alexandr11 [23.1K]
From the diagram;
1. Angle 2 = ADB+BDH
                                           = arcAB/2 +90 
                                           = 34 +90 
                                           = 124°

2. Angle 4= 90°,
Reason ; the angle between a tangent and a radius is equal to 90. A tangent is a line that touches the circumference of a circle once even if prolonged.

3. Angle 5 = 90 -BDC (note the acr subtends twice the angle it subtends on the circumference to the center.
             = 90-arc BC/2
             = 90-36
              = 54°

4. Angle 6 = BFD
             = 180-ADB-FBD
             = 180-AB/2-DE/2
             But DE = 180 -121 = 59
Therefore, BFD = 180 -34-29.5
             = 116.5°

5. Angle 1 = 180- BFD (angles on a straight line add up to 180°)
              = 180- 116.5
              = 63.5°
           

6. Angle 3 = 180 -(ADB+BFD)
             = 180 -(34 +116.5)
             =  180- 150.5
             = 29.5°
similarly angle 3 = DE/2 = 59/2 = 29.5°

7. Angle 8= 90, because BD is diameter;
 angles subtended by a diameter to the circumference is always a right angle (90°)


8.Angle 7 =  BE
               but BE= AB+AE
                          = 68+ 53
                          = 121°
                 


    
3 0
3 years ago
Please solve<br>I really need help​
Llana [10]

9514 1404 393

Answer:

  x = 12

Step-by-step explanation:

The similarity statement tells you corresponding sides have the same ratio.

  AB/BC = FE/EC

  x/10 = 6/5

  x = 10(6/5)

  x = 12

7 0
3 years ago
Graph the system of linear inequalities, please explain the process in solving this problem so I know how to do ones similar to
Ierofanga [76]

Graph the system of linear inequalities

x + y > 5

- x - y < -5

First we graph x + y >5

Step 1: replace > symbol by = sign

x + y =5

step 2 : Solve the equation for y

x + y =5 (subtract x from both sides)

y = 5 - x

step 3: Now we make a table . plug in some number for x  and find out y

x -----> y

-1 -----> 6   ( y=5-x => y=5-(-1)= 6)

0 -----> 5   ( y=5-x => y=5-(0)= 5)

1 -----> 4   ( y=5-x => y=5-(1)= 4)

Step 4:  we graph the table.

step 5: Shade the region that satisfies our inequality

x + y > 5. Greater than symbol implies that we shade the graph to the right

Graphing second inequality - x - y < -5

All terms have negative sign . so divide all the terms by -1. When we divide an inequality by -1 its sign changes

- x - y < -5 becomes x + y > 5

Follow the same steps to graph this inequality

After dividing the second equation  by -1 , we got the same as the first equation.

So we will get the same graph

Both graphs overlaps

The graph of first and second inequality overlaps

The graph is attached below

4 0
3 years ago
Hijsjsjsjsjdjej jejdjwjejd
Alenkasestr [34]

Answer:

BC=11.9

Step-by-step explanation:

7 0
2 years ago
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