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3 years ago

On his trip,Buddy drove 60 mph for 1 hour, 55 mph for 3 hours and 40 mph for 2 hours. What was the distance of Buddy trip?

Mathematics

2 answers:

max2010maxim [7]3 years ago

5 0

Answer: 305 miles

Step-by-step explanation: (60 times 1) + (55 times 3) + (40 times 2) = 305 miles

hodyreva [135]3 years ago

3 0

Answer:

I think its 305

Step-by-step explanation:

60x1=60. 55x3=165. 40x2=80. 60+164+80= 305.

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What is the value of x?

stich3 [128]

Answer:I think the answer is x=25 sorry if im wrong ツ.

Step-by-step explanation:

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3 years ago

Lucy has 1/5 of a pound of chocolates. She would like to make 4 gift bags with chocolates for her teachers.

Lapatulllka [165]

Answer:

0.05 pound of chocolate per gift bag or 1/20 pound of chocolate per gift bag

Step-by-step explanation:

1/5 divided by 4

=0.05 pound of chocolate per gift bag or 1/20 pound of chocolate per gift bag

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2 years ago

What is the value of b in the equation (y)*

KonstantinChe [14]

Answer:

b = -6

Step-by-step explanation:

Apply the exponent rule that $\frac{1}{x^{n}} = x^{-n}$

In this case, $\frac{1}{y^{24}} = y^{-24}$

Set that equal to $(y^{b})^{4}$ :

$(y^{b})^{4} = y^{-24}$

Apply the exponent rule that $(x^{m})^{n} = x^{mn}$ so now you get:

$y^{4b} = y^{-24}$

Since the base is y for both sides of the equation, just set the exponents equal to each other and solve for b.

4b = -24

divide each side by 4 to get:

b = -6

6 0

2 years ago

Dany bought a total of 20 game cards some

elixir [45]

12 cards : $0.25
8 cards : $0.15

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3 years ago

Chose parameters h and k such that the system has a) a unique solution, b) many solutions, and c) no solution. X1 + 3x2 = 4 2x1

AysviL [449]

Answer:

a) The system has a unique solution for $k\neq 6$ and any value of $h$ , and we say the system is consisted

b) The system has infinite solutions for $k=6$ and $h=8$

c) The system has no solution for $k=6$ and $h\neq 8$

Step-by-step explanation:

Since we need to base the solutions of the system on one of the independent terms ( $h$ ), the determinant method is not suitable and therefore we use the Gauss elimination method.

The first step is to write our system in the augmented matrix form:

$\left[\begin{array}{cc|c}1&3&4\\2&k&h\end{array}\right]$

The we can use the transformation $r_0\rightarrow r_0 -2r_1$ , obtaining:

$\left[\begin{array}{cc|c}1&3&4\\0&k-6&h-8\end{array}\right]$ .

Now we can start the analysis:

If $k\neq 6$ then, the system has a unique solution for any value of $k$ , meaning that the last row will transform back to the equation as:

$(k-6)x_2=h-8\\x_2=h-8/(k-6)$

from where we can see that only in the case of $k=6$ the value of $x_2$ can not be determined.

if $k=6$ and $h=8$ the system has infinite solutions: this is very simple to see by substituting these values in the equation resulting from the last row:

$(k-6)x_2=h-8\\0=0$ which means that the second equation is a linear combination of the first one. Therefore, we can solve the first equation to get $x_1$ as a function of $x_2$ o viceversa. Thus, $x_2$ ( $x_1$ ) is called a parameter since there are no constraints on what values they can take on.

if $k=6$ and $h\neq 8$ the system has no solution. Again by substituting in the equation resulting from the last row:

$(k-6)x_2=h-8\\0=h-8$ which is false for all values of $h\neq 8$ and since we have something that is not possible $(0\neq h-8,\ \forall \ h\neq 8)$ the system has no solution

6 0

3 years ago