Lets put these numbers in order
1,2,3,3,4,5,6,7,8,8,9
Q1 = 3
Q2 (median) = 5
Q3 = 8
the box starts at Q1 and ends at Q3....so left side is 3 and right side is 8
u r correct...it is A
Answer:
um
Step-by-step explanation:
9514 1404 393
Answer:
see below
Step-by-step explanation:
Setting x=0, you can find the y-intercept:
y = 4
Setting y = 0, you can find the x-intercept:
2x = 4
x = 2
The boundary line can be drawn through these intercept points, (0,4) and (2,0). Because the "equal to" case is not included, the boundary line will be dashed.
The y variable is on the open side of the comparison symbol (y>), so the shading is above the boundary line. That is where y-values are greater than those on the line.
Answer:
![yes \: he \: is \: correct \\ \underline{\boxed{(\triangle{ \delta}) = 8}}](https://tex.z-dn.net/?f=yes%20%5C%3A%20he%20%5C%3A%20is%20%5C%3A%20correct%20%5C%5C%20%20%20%5Cunderline%7B%5Cboxed%7B%28%5Ctriangle%7B%20%5Cdelta%7D%29%20%3D%208%7D%7D)
Step-by-step explanation:
![change \: in \: temp. \: ( \triangle{ \delta}) = t_2 - t_1 \\ hence \to \\( \triangle{ \delta}) = (- 2) - (- 10) \\ (\triangle{ \delta}) = - 2 + 10 \\ (\triangle{ \delta}) = 10 - 2 \\ (\triangle{ \delta}) = 8](https://tex.z-dn.net/?f=change%20%5C%3A%20in%20%5C%3A%20temp.%20%5C%3A%20%28%20%5Ctriangle%7B%20%5Cdelta%7D%29%20%3D%20t_2%20-%20t_1%20%5C%5C%20hence%20%5Cto%20%5C%5C%28%20%5Ctriangle%7B%20%5Cdelta%7D%29%20%3D%20%20%28-%202%29%20-%20%28-%2010%29%20%5C%5C%20%28%5Ctriangle%7B%20%5Cdelta%7D%29%20%3D%20%20-%202%20%2B%2010%20%5C%5C%20%28%5Ctriangle%7B%20%5Cdelta%7D%29%20%3D%2010%20-%202%20%5C%5C%20%28%5Ctriangle%7B%20%5Cdelta%7D%29%20%3D%208)