Translate the phrase into an algebraic expression. The difference of x and 5
1 answer:
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PROBLEM ONE
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Solving for x in 2x + 5y > -1.
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Step 1 ) Subtract 5y from both sides.
2x + 5y > -1
2x + 5y - 5y > -1 - 5y
2x > -1 - 5y
Step 2 ) Divide both sides by 2.
2x > -1 - 5y
So, the solution for x in 2x + 5y > -1 is...
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Solving for y in 2x + 5y > -1.
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Step 1 ) Subtract 2x from both sides.
2x + 5y > -1
2x - 2x + 5y > -1 - 2x
5y > -1 - 1x
Step 2 ) Divide both sides by 5.
5y > -1 - 1x
So, the solution for y in 2x + 5y > -1 is...
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PROBLEM TWO
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Solving for x in 4x - 3 < -3.
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Step 1 ) Subtract 3 from both sides.
4x - 3 < -3
4x -3 - 3 < -3 - 3
4x < 0
Step 2 ) Divide both sides by x.
4x < 0
x < 0
So, the solution for x in 4x - 3 < -3 is...
x < 0
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- <em>Marlon Nunez</em>