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2 years ago

Translate the phrase into an algebraic expression. The difference of x and 5

Mathematics

1 answer:

nikklg [1K]2 years ago

6 0

Answer:

x - 5 = y

Step-by-step explanation:

i think it's correct

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how to right 50 billion in Scientific Notation please help i will give brainlynest answer i need in 3 min tops please help

ValentinkaMS [17]

Hi,

So 50 billion written out would be 50,000,000,000

In scientific notation that would be 5.0 x 10^10

6 0

3 years ago

Show a way to count from 668 to 900 using ones tens and hundreds

cricket20 [7]

Hey there!

You can count from 668 to 900 using the following:

668 → 768 → 868 (two 100s)

868 → 878 → 888 → 898 (three 10s)

898 → 899 → 900 (two 1s)

Hope this helped you out! :-)

7 0

3 years ago

Read 2 more answers

6.Suppose the Gallup Organization wants to estimate the population proportion of those who think there should be a law that woul

drek231 [11]

Answer:

A sample of $n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$ is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In a previous study of 1012 randomly chosen respondents, 374 said that there should be such a law.

This means that $n = 1012, \pi = \frac{374}{1012} = 0.3696$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

How large a sample size is needed to be 95% confident with a margin of error of E?

A sample size of n is needed, and n is found when M = E.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$E = 1.96\sqrt{\frac{0.3696*0.6304}{n}}$

$E\sqrt{n} = 1.96\sqrt{0.3696*0.6304}$

$\sqrt{n} = \frac{1.96\sqrt{0.3696*0.6304}}{E}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$

$n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$

A sample of $n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$ is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

4 0

3 years ago

Se arrastra un bloque de 18 kg a través de una superficie con una fuerza de 300 N en donde el coeficiente de fricción de dicha s

ozzi

Answer:

$10.9\ \text{m/s}^2$