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astra-53 [7]
2 years ago
13

URGENT! NEED SOMEONE TO PROPERLY CALCULATE FOR DEGREES BECAUSE MY CALCULATOR DOESN'T GIVE RIGHT ANSWER FOR SOME REASON!

Mathematics
2 answers:
ella [17]2 years ago
7 0
Cos^-1 (21.6/48.2) ≈ 63.37°<span>

tan^-1 (6.7/13.7) </span>≈ 26.06°
Morgarella [4.7K]2 years ago
3 0
The first one is 63.37605197 and the second one is 26.06099574
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The average amount parents and children spent per child on back-to-school clothes in Autumn 2010 was $527. Assume the standard d
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Answer: a. 0.14085

b. 3.826 x 10^{-3}

c.  0.5437

d. 0.0811  

Step-by-step explanation:

Given average amount parents and children spent per child on back-to-school clothes in Autumn 2010 , \mu = $527

Given standard deviation , \sigma = $160

Let X = amount spent on a randomly selected child

Also Z = \frac{X-\mu}{\sigma}

a. Probability(X>$700) = P(\frac{X-\mu}{\sigma} > \frac{700-527}{160}) = P(Z>1.08125) = 0.14085 {Using Z % table}

b. P(X<100) = P( Z < \frac{100-527}{160}) = P(Z< -2.66875) = P(Z > 2.66875) = 3.826 x 10^{-3}

c. P(450<X<700) = P(X<700) - P(X<=450)

   P(X<700) = 1 - P(X>=700) = 1 - 0.14085 = 0.8592

   P(X<=450) = P(Z<= \frac{450-527}{160}) = P(Z<= -0.48125) = P(Z<=0.48125) = 0.3155

   So final   P(450<X<700) =  0.8592 - 0.3155 = 0.5437

d. P(X<=300) = P(Z<= \frac{300-527}{160}) = P(Z<= -1.4188) = P(Z>=1.4188) = 0.0811                                                                        

All the above probabilities are calculated using Z % table along with interpolation between two values.

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1/2 = 3/6
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3/6 = 1/6x
X = 3, she has 3 children
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Answer:

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John is six year older than Bill. If their combined
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John is 21 and bill is 15

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