Step-by-step explanation: need to find a basis for the solutions to the equation Ax = 0. To do this ... 0 0 0 1 −3. ⎤. ⎦. From this we can read the general solution, x = ⎡. ⎢. ⎢. ⎢. ⎢. ⎣ ... two vectors are clearly not multiples of one another, they also give a basis. So a basis ... 4.4.14 The set B = {1 − t2,t − t2,2 − 2t + t2} is a basis for P2.

4 0

2 years ago

J is the midpoint of KL. The coordinates of J are (-8,7) and the coordinates of K are (3,4) find the coordinates of L. (show wor

musickatia [10]

Assuming linear.
if k is at (3,4) and j is at (-8,7)
set. (y1,x1) and(y2,x2)

[(y2-y1),(x2-x1)]
[(-8-3),(7-4)]
distance from k to j is (-11,3)

now take coordinates of j and distance from. k->j and add them to get coordinate for L

[(-11+(-8)),(7+3)]= (-19,10)=L

7 0

3 years ago