The statements true about the the function f(x) = 2x2 – x – 6 are-
- The vertex of the function is (one-quarter, negative 6 and one-eighth).
- The function has two x-intercepts.
<h3>What is vertex of parabola?</h3>
The vertex of parabola is the point at the intersection of parabola and its line of symmetry.
Now the given function is,
f(x) = 2x^2 – x – 6
Also, it is given that the vertex is located at (0.25, -6) and the parabola opens up, the function has two x-intercepts.
Comparing the given function with standard form,
f(x) = a x^2 bx + c
By comprison we get,
a = 2
b = -1
c = -6
Now, x-coordinate of vertex is given as,
x = -b/2a
put the values we get,
x = -(-1)/2*2
or, x = 1/4
Put the value of x in given function, so y-coordinate of the vertex is given as,
f(1/4) = 2(1/4)² - 1/4 - 6
= -49/6
= -6 1/8
Hence, The statements true about the the function f(x) = 2x2 – x – 6 are-
- The vertex of the function is (one-quarter, negative 6 and one-eighth).
- The function has two x-intercepts.
More about vertex :
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Answer:
the answer is x=0 and x=2
Step-by-step explanation:
Answer:
25/42
Step-by-step explanation:
first find same denominators
18/42 + 7/42
then add the new fractions
18/42 + 7/42 = 25/42
Hope this helps :)
Have a nice day :)
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Answer:
155
Step-by-step explanation:
⇒I will first isolate y together with its coefficient k by placing 
to the right hand side...
⇒Now to leave y independent we have to divide ky by the coefficient of y which in this case is k.
⇒Meaning k will divide all the terms in the equation.
⇒Attached is the answer.
